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3 years ago

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Does anyone know how to find the answer key to this?

1 answer:

Mrrafil [7]3 years ago

8 0

It’s better to donintuourself it’s better to do it yourself and learn it

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When a positively charged conductor touches a neutral conductor, the neutral conductor will:

frutty [35]

Answer:

Lose electrons

Explanation:

When a positively charged conductor touches a neutral conductor, the neutral conductor will lose electrons. Only electrons can move from one conductor to another, so if the neutral conductor ended up with a positive charge it means it lost electrons. The conductor touching and the neutral conductor both end up being charged positively.

6 0

4 years ago

An car has an acceleration of 8.0 m/s/s. How much time is needed to reach a velocity of 30 m/s from

polet [3.4K]

Answer:

3.75s

Explanation:

a = 8.0 m/s V = 30 m/s U = 0 m/s t = ?

t = V - U/a

t = 30 - 0/8

t = 30/8 = 15/4

t = 3.75s

5 0

3 years ago

When a certain gas under a pressure of 4.90 106 pa at 20.0°c is allowed to expand to 3.00 times its original volume, its final p

Elina [12.6K]

As per question the initial states of the gases are given as

INITIAL STATE: FINAL STATE:

$p_{1} =4.90106 pa$ $p_{2} =1.06106 pa$

$v_{1} =v[say]$ $v_{2} =3v[say]$

$T_{1} =20 degree celcius =293 K$ $T_{2} =?$

AS per combined gas equation obtained from the combination of Boyle's law and Charles law [Basic ideal gas laws]

$\frac{p_{1} v_{1} }{T_{1} } =\frac{p_{2}v_{2} }{T_{2} }$

Hence $T_{2} =\frac{p_{2} v_{2}T_{1} }{p_{1} v_{1} }$

= $\frac{1.06106*3v*293}{4.90106*v}$

=190.3 K [ANS]

6 0

3 years ago

A 2.5-m-long steel shaft of 30-mm diameter rotates at a frequency of 35 Hz. Determine the maximum power that the shaft can trans

Phantasy [73]

Answer:

$P=58.3kW$

Explanation:

Given data

Length L=2.5 m

Radius R=d/2=30/2 = 15 mm

Torque based on allowable stress

Allowable shear stress τ=50 Mpa

Allowable torque T=(π/2)τc³

$T=\frac{\pi }{2}(50*10^{6} )(0.015)^{3} \\ T=264.94N.m$

Torque based on allowable angle of twist

Allowable Angle of twist

Ф=7.5°

Ф=7.5×(π/180)=130.90×10⁻³ rad

Allowable torque

T=(GJФ)/L

T=(G(π/2)c⁴)Ф)/L

T=(πGc⁴Ф)/2

$T=\frac{\pi (77.2*10^{9} )(0.015)^{4}(130.90*10^{-3} ) }{2}\\ T=265.07N.m$

Maximum Power Transmitted

Maximum power transmitted is given by

$P=2\pi fT\\P=2\pi (35)(265.07)\\P=58262.386watt\\P=58.3kW$

6 0

4 years ago

A certain superconducting magnet in the form of a solenoid of length 0.24 m can generate a magnetic field of 7.0 T in its core w

tatiyna

Answer:

$N=14854.5turns$

Explanation:

Given data

Length L=0.24 m

Magnetic field B=7.0 T

Current I=90 A

To find

Number of turns N

Solution

As we know that magnetic field is given as:

$B=u_{o}I\frac{N}{L}$

Rearrange the equation and solve for N

So

$B=u_{o}I\frac{N}{L}\\\frac{B}{u_{o}I} =\frac{N}{L} \\N=\frac{LB}{u_{o}I}\\N=\frac{(0.24m)(7.0T)}{4\pi *10^{-7}*(90A)} \\N=14854.5turns$

5 0

3 years ago