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NeTakaya
3 years ago
11

Does anyone know how to find the answer key to this?

Physics
1 answer:
Mrrafil [7]3 years ago
8 0
It’s better to donintuourself it’s better to do it yourself and learn it
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A small object begins a free-fall from a height of =81.5 m at 0=0 s . After τ=2.20 s , a second small object is launched vertica
-BARSIC- [3]

Answer:

33.2 m

Explanation:

For the first object:

y₀ = 81.5 m

v₀ = 0 m/s

a = -9.8 m/s²

t₀ = 0 s

y = y₀ + v₀ t + ½ at²

y = 81.5 − 4.9t²

For the second object:

y₀ = 0 m

v₀ = 40.0 m/s

a = -9.8 m/s²

t₀ = 2.20 s

y = y₀ + v₀ t + ½ at²

y = 40(t−2.2) − 4.9(t−2.2)²

When they meet:

81.5 − 4.9t² = 40(t−2.2) − 4.9(t−2.2)²

81.5 − 4.9t² = 40t − 88 − 4.9 (t² − 4.4t + 4.84)

81.5 − 4.9t² = 40t − 88 − 4.9t² + 21.56t − 23.716

81.5 = 61.56t − 111.716

193.216 = 61.56t

t = 3.139

The position at that time is:

y = 81.5 − 4.9(3.139)²

y = 33.2

7 0
3 years ago
A rocket powered sled accelerates a jet pilot in training straight forward from rest to 270 km/h in 12.1 seconds. Find:
Ilia_Sergeevich [38]

Answer:

  1. 6.198 m/s²
  2. 4.48 s
  3. 453.77 m

Explanation:

5 0
3 years ago
Determine the direction in which an electrical signal is carried in a typical multipolar neuron
choli [55]
The direction in which an electrical signal is carried in a typical multi-polar neuron is:
Dendrites, cell body, axon
Specialized projection of neurons are dendrites and axon. The central part of neuron is cell body. So, the electrical signal is carried in a direction that first dendrites carried the signal then it goes towards cell body and then to axon.
6 0
3 years ago
Apakah soalan tingkatan 4 bm negeri selangor
noname [10]
What does this mean? What do you need help with?
8 0
3 years ago
a 60 kg woman in a elevator is accelerating upward at a rate of 1.2 m/s2. What is the gravitational force acting upon the woman?
Flura [38]

The gravitational force acting upon the woman is equal to <u>-588.6N</u>

Why?

To solve the problem, we need to consider that two forces are acting upon the woman, the first one is related to her weight and the second one is related to the acceleration of the elevator.

Gravitational force acting upon the woman:

Force=m*gravityacceleration\\\\Force=60kg*-9.81\frac{m}{s^{2}}=-588.6N

Hence, we have that the gravitational force acting upon the woman is equal to -588.6N.

Have a nice day!

5 0
2 years ago
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