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NeTakaya
3 years ago
11

Does anyone know how to find the answer key to this?

Physics
1 answer:
Mrrafil [7]3 years ago
8 0
It’s better to donintuourself it’s better to do it yourself and learn it
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when huburxvkruxv hfgy

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Un hombre de pie puede ejercer la misma fuerza con sus piernas tanto en la tierra como en la luna. Sabemos que la masa del hombr
Paul [167]

Answer:

The height jumped by the person on the moon is 6 times the height jumped by the person on earth.  

Explanation:

As we know that the acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.

So, it is false.

Let the mass of man is m and the gravity on moon is g' = g/6.

Let the height jumped on earth is h and the height jumped on moon is h'.

So,

m x g' x h' = m x g x h

g/6 x h' = g x h

h' = 6 h  

So, the height jumped by the person is 6 times the height jumped by the person on earth.

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3 years ago
If a tank filled with water contains a block and the height of the water above point A within the block is 0.6 meter what’s the
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4 years ago
When you look out the window you can see constantly moving air. Air is cycled in order to reach equilibrium. Answer the followin
svet-max [94.6K]
So base on your question about the moving air and its is cycled in order to reach equilibrium the answer of the questions are the following 
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<span>B. how does these characteristics change the movement of air? 
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5 0
3 years ago
Read 2 more answers
A mass with a charge of 4.60 x 10-7 C rests on a frictionless surface. A compressed spring exerts a force on the mass on the lef
stira [4]

Answer:

The compression of the spring is 24.6 cm

Explanation:

magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C

magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C

distance between the two charges, r = 3 cm = 0.03 m

spring constant, k = 14 N/m

The attractive force between the two charges is calculated using Coulomb's law;

F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(4.6\times 10^{-7})(7.5\times 10^{-7})}{(0.03)^2} \\\\F= 3.45 \ N

The extension of the spring is calculated as follows;

F = kx

x = F/k

x = 3.45 / 14

x = 0.246 m

x = 24.6 cm

The compression of the spring is 24.6 cm

4 0
3 years ago
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