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shusha [124]
3 years ago
10

I need help with this!

Chemistry
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

2.68 cm^3

Explanation:

Density= Mass/Volume

so...

8.96 g/cm^3 = 24.01 g/ V

and then u solve so it would be 2.68 cm ^3

((:

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The plunger on a bicycle pump with a 400 mL volume cylinder is
Kobotan [32]

Answer:

The answer to your question is V2 = 66.7 ml

Explanation:

Data

Volume 1 = V1 = 400 ml

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = ?

Pressure 2 = P2 = 6 atm

Process

1.- To solve this problem use Boyle's law

                     P1V1 = P2V2

-solve for V2

                     V2 = P1V1 / P2

-Substitution

                      V2 = (1)(400) / 6

-Simplification

                      V2 = 400 / 6

-Result

                      V2 = 66.7 ml

4 0
3 years ago
Lab Report
Alenkasestr [34]

Answer:

I know some of them...

Explanation:

1. What was the purpose of the experiment?

Type your answer here: The purpose of this experiment is to show that a cell membrane is a type of barrier, and is permeable to some substances, but may not be permeable to all substances.

2. What were the independent, dependent, and control variables in your investigation? Describe the variables used in the part of the experiment with the eggs.

Type your answer here: Independent variable / Manipulated variable: Refers to all the variables in an experiment that provoke a response in another variable. This variable is modified during the experiment to analyze how another variable responds to it. The researcher wants to study how the changes in these variables affect the dependent variable.  The researcher can change these variables to see what changes it implies in an object, process, trait, or anything that depends on them.

Dependent variable / Responding variable: Its response depends on any change in the independent variable. The dependent variable is the one that is being investigated, studied, and measured. It represents a quantity of something which value depends on how the independent variable is modified. It is usually identified by the letter Y.  A change in the dependent variable might be proportional or inversely proportional to the change in the manipulated variable. In the exposed example, the dependent variable is the egg circumference.

Constants / Controlled variables: Refers to those variables in an experiment that are controlled and have no influence on the results. These variables do not affect the change in the dependent variable values. In the exposed example the use of the lid to seal the jar and the amount and concentration of vinegar might be considered as a controlled variable. These elements are used but do not provoke any change in the size of the egg.

thats it... CAN SOMEONE ANSWER THE OTHERS?! I NEED ITT

4 0
3 years ago
How many grams of H2O are in 34.2 grams of NAOH<br> Need ASAP
Brrunno [24]

Answer:

15.438g H2O

Explanation:

First you need to find the reaction equation:

2H2O+2Na=2NaOH + H2

Hydrogen is a diatomic molecule so it will have a subscript of 2 on the right hand side. From there we can balance the reaction.    

Then we can use stoichiometry:

34.2g NaOH * (1 mol NaOH/39.908g NaOH) * (2 mol H2O/2 mol NaOH) * (18.015g H2O/1 mol H20) = 15.438g H2O

It is important that when you use stoichiometry that all your units cancel out until you only have the unit you want.

3 0
2 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
We can consider a chemical to be safe if:
slamgirl [31]
We can consider a chemical to be safe if it does not contain any harmful substances such as nitrogen, harmful acids, or even excessive heat. Other chemicals such as the chemicals used in food products like, for example, citric acid, is not so harmful.
Hope this helps! :D
Any questions? Just let me know! I'd be happy to help any way possible.
8 0
3 years ago
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