The answer is 4.9 moles.
Solution:
Using the equation for boiling point elevation Δt,
Δt = i Kb m
we can rearrange the expression to solve for the molality m of the solution:
m = Δt / i Kb
Since we know that pure water boils at 100 °C, and the Ebullioscopic constant Kb for water is 0.512 °C·kg/mol,
m = (105°C - 100°C) / (2 * 0.512 °C·kg/mol)
= 4.883 mol/kg
From the molality m of the solution of salt added in a kilogram of water, we can now find the number of moles of salt:
m = number of moles / 1.0kg
number of moles = m*1.0kg
= (4.883 mol/kg) * (1.0kg)
= 4.9 moles
Answer:
Answer is option B . This is because water is said to be highly permeable to the underground soil and thus nourishes it , whereas capillary action will make the water flow upward sllowly , but the water is going underground so it is permeability. Also soil is porous too , but that's only if the water is in the soil , here the water is caused to go underground by some force , so porosity isnt the right option
Explanation:
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Explanation:
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Answer:
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Explanation:
