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shusha [124]
3 years ago
10

I need help with this!

Chemistry
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

2.68 cm^3

Explanation:

Density= Mass/Volume

so...

8.96 g/cm^3 = 24.01 g/ V

and then u solve so it would be 2.68 cm ^3

((:

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How many bromine atoms are present in 37.9 g of CH2Br2?
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Answer:

The answer to your question is: 6.55 x 10 ²³ atoms of Br

Explanation:

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MW CH2Br2 = (12 x 1) + (2 x 1) + (80 x 2) = 174 g

                   174 g of CH2Br2 ------------------  160 g of Br2

                   37.9 g of CH2Br2   ---------------     x

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                         x              ----------------    174 g Be2

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            1.088 mol of Br -------------    x

                    x = 1.088 x 6.023 x 10 ²³ / 1 = 6.55 x 10 ²³ atoms

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