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3 years ago

10

After a day of testing race cars, you decide to take your own 1550 kg car onto the test track. While moving down the track at 10

.0 m/s, you uniformly accelerate to 25.0 m/s in 10 s. What is the average net force that you have applied to the car during the 10 s interval?

2 answers:

kondor19780726 [428]3 years ago

8 0

Answer:

2325 N

Explanation:

mass, m = 1550 kg

initial velocity, u = 10 m/s

final velocity, v = 25 m/s

time, t = 10 s

acceleration, a = ( v - u) / t

a = (25 - 10) / 10

a = 1.5 m/s²

Force, F = mass x acceleration

F = 1550 x 1.5 = 2325 N

Thus, the force is 2325 N.

quester [9]3 years ago

6 0

Answer:

F = 2325 N

Explanation:

given,

mass of the car, m = 1550 Kg

initial speed, u = 10 m/s

final speed, v = 25 m/s

time, t = 10 s

Average net force = ?

acceleration of the car

$a = \dfrac{v-u}{t}$

$a = \dfrac{25-10}{10}$

a = 1.5 m/s²

we know

F = m a

F = 1550 x 1.5

F = 2325 N

Net average force applied on the car is equal to 2325 N.

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