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Nastasia [14]
3 years ago
10

After a day of testing race cars, you decide to take your own 1550 kg car onto the test track. While moving down the track at 10

.0 m/s, you uniformly accelerate to 25.0 m/s in 10 s. What is the average net force that you have applied to the car during the 10 s interval?
Physics
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer:

2325 N

Explanation:

mass, m = 1550 kg

initial velocity, u = 10 m/s

final velocity, v = 25 m/s

time, t = 10 s

acceleration, a = ( v - u) / t

a = (25 - 10) / 10

a = 1.5 m/s²

Force, F = mass x acceleration

F = 1550 x 1.5 = 2325 N

Thus, the force is 2325 N.

quester [9]3 years ago
6 0

Answer:

F = 2325 N

Explanation:

given,

mass of the car, m = 1550 Kg

initial speed, u = 10 m/s

final speed, v = 25 m/s

time, t = 10 s

Average net force = ?

acceleration of the car

a = \dfrac{v-u}{t}

a = \dfrac{25-10}{10}

a = 1.5 m/s²

we know

F = m a

F = 1550 x 1.5

F = 2325 N

Net average force applied on the car is equal to 2325 N.

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Which evidence taken from a crime scene would be the best evidence for a District Attorney to gain a conviction with DNA evidenc
mezya [45]

Answer:

Blood

Explanation:

All the mentioned option will yield the same DNA for the suspect but blood, besides the DNA also contain further information that can be matched to the victim like blood group, genotype, some antibodies present and even traces of substances and disease.

6 0
3 years ago
Calculate the change in entropy as 0.3071 kg of ice at 273.15 K melts. (The latent heat of fusion of water is 333000 J / kg)
Ostrovityanka [42]

Answer:

374.39 J/K

Explanation:

Entropy: This can be defined as the degree of disorder or randomness of a substance.

The S.I unit of entropy is J/K

ΔS = ΔH/T ..................................... Equation 1

Where ΔS = entropy change, ΔH = Heat change, T = temperature.

ΔH = cm................................... Equation 2

Where,

c = specific latent heat of fusion of water = 333000 J/kg, m = mass of ice = 0.3071 kg.

Substitute into equation 2

ΔH = 333000×0.3071

ΔH = 102264.3 J.

Also, T = 273.15 K

Substitute into equation 1

ΔS = 102264.3/273.15

ΔS = 374.39 J/K

Thus, The change in entropy = 374.39 J/K

3 0
2 years ago
After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of 2.85 m/s. T
motikmotik

Answer:

V' = 0.84 m/s

Explanation:

given,

Linear speed of the ball, v = 2.85 m/s

rise of the ball, h = 0.53 m

Linear speed of the ball, v' = ?

rotation kinetic energy of the ball

KE_r = \dfrac{1}{2}I\omega^2

I of the moment of inertia of the sphere

I = \dfrac{2}{5}MR^2

 v = R ω

using conservation of energy

KE_r = \dfrac{1}{2}( \dfrac{2}{5}MR^2)(\dfrac{V}{R})2

KE_r = \dfrac{1}{5}MV^2

Applying conservation of energy

Initial Linear KE + Initial roational KE = Final Linear KE + Final roational KE + Potential energy

\dfrac{1}{2}MV^2 + \dfrac{1}{5}MV^2 = \dfrac{1}{2}MV'^2 + \dfrac{1}{5}MV'^2 + M g h

0.7 V^2 = 0.7 V'^2 + gh

0.7\times 2.85^2 = 0.7\times V'^2 +9.8\times 0.53

V'² = 0.7025

V' = 0.84 m/s

the linear speed of the ball at the top of ramp is equal to 0.84 m/s

6 0
3 years ago
A truck is traveling at 2.0 m/s. It slows to a stop at a constant rate over 3.00 s. How far does the car travel during those 3.0
earnstyle [38]

Answer:

During those 3.00 seconds before stopping, the car travels a distance of 6 m.

Explanation:

The simple rule of three is a tool that is used to quickly solve problems, where three pieces of information must be known, and one of them operates as an unknown to be known.

Two magnitudes are directly proportional if one magnitude increases the other also does it, and if the magnitude decreases the other in the same way.

Being a, b and c known data and x the unknown, the value that we want to know, the rule of three when the magnitudes are directly proportional is applied as follows:

a ⇒ b

c ⇒ x

So: x=\frac{c*b}{a}

In this case, knowing that a truck travels at 2 m/s, the rule of three applies as follows: if in 1 second the truck travels 2 m, in 3 seconds how much distance does it travel?

distance=\frac{3 s*2 m}{1 s}

distance= 6 m

<u><em> During those 3.00 seconds before stopping, the car travels a distance of 6 m.</em></u>

8 0
3 years ago
Why won't a very bright beam of red light impart more energy to an ejected electron than a feeble beam of violet light?
bearhunter [10]
This is related to the energy carried by photons of light the energy of each photon is proportional to the frequency of the light since red light has a lower frequency then violet light and photons of red light carry less energy than the photons of violet light as a result the red protons eject electrons that have less energy than the ejected electrons by Violet photons
3 0
2 years ago
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