How much energy (in J) is lost when a sample of iron with a mass of 26.4 g cools from 74.0 ∘C to 26.0 ∘C?

Chemistry

1 answer:

Greeley [361]4 years ago

8 0

Answer:

$Q=-526.6J$

Explanation:

Hello,

In this case, for the computation of the energy loss when the cooling process is carried out, we use the shown below equation:

$Q=mCp\Delta T$

Whereas we need the mass, specific heat and change in temperature of iron within the process. Thus, the only value we need is the specific heat that is 0.444 J/(g°C), therefore, we compute the heat loss:

$Q=26.4g*0.444\frac{J}{g\°C}*(26.0\°C-74.0\°C)\\ \\Q=-526.6J$

Negative sign points out the loss due to the cooling.

Regards.

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