Answer:
Final concentration = 0.019 M
Explanation:
Initial Concentration [A]o = 0.27M
Rate constant, k = 0.75 s^-1
Final concentration [A] = ?
Time, t = 1.5s
The relationship between the variables is given by the equation;
ln[A] = ln[A]o - kt
ln[A] = ln(0.27) - (0.75)(1.5)
ln[A] = - 1.309 - 1.125
ln[A] = - 2.434
[A] = 0.019 M
Answer:
<em>The type of vegetation a surface does affect the </em><em>water coming from above to sink in or runoff. </em>
Explanation:
This is how the vegetation affects the runoff:-
The leaves and stems present in the vegetation do not let the water fall directly on the soil and makes the process rather slow which makes the water to get to the ground slowly and sink in properly inside the soil rather than running off.
If the vegetation present is dense with there was being hairy then also the water would not run out and will get absorbed by the roots letting the soil intact
88g ( so sorry if this isn’t correct )
The volume occupied by 2.00 moles of nitrogen gas at the same temperature and pressure will be
0.500 moles = 11.2 Liters
what about 2 moles =? liters
by cross multiplication
= 11.2 liters x 2moles/ 0.500 moles = 44.8 liters
Answer:
2 CH2 + 3 O2 = 2 CO2 + 2 H2O
Explanation:
This is what I think that you meant by the question listed. When balancing a chemical equation, you want to make sure that there are equal amounts of each element on each side.
Originally, the equation's elements looked like this: 1 C on left & 1 C on right; 2 H on left & 2 H on right; 2 O on left and 3 O on right. Because these are not balanced, you need to add coefficients.
When adding coefficients, you need to make sure that all of the elements stay balanced, not just one that you are trying to fix. I know that some equations are really difficult to balance, and when that is the case, there are equation balancing websites that can help out.
However, what always helps me is making a chart and continuing to keep up with the changes I am making. It is a trial and error process.
