All categories

3 years ago

Help me plssss 30 pointsssssss

Physics

2 answers:

labwork [276]3 years ago

6 0

Answer:

Explanation:

viva [34]3 years ago

5 0

Answer:

Light

sound

electrical

chemical

mechanical

Explanation:

Hope this helps!!

You might be interested in

The conductive tissues of the upper leg can be modeled as a 40-cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivi

ahrayia [7]

To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.

The equation that is responsible for relating the two variables is:

$R = \rho \frac{L}{A}$

Where,

R= Resistance of the conductor

$\rho =$ Resistivity of the conductor material

L = Length

A = Cross-sectional area of conductor

With the previous values the area of the muscle (Real Muscle-82%)is,

$A_m = (0.82)\pi r^2 = (0.82)\pi (12/2*10^{-2})^2$

$A_m = 9.274*10^{-3}m^2$

Using the equation from Resistance we have that at the muscle the value is:

$R_m = \rho \frac{L}{A}$

$R_m = \frac{13*(0.4)}{9.274*10^{-3}}$

$R_m = 560.70\Omega$

At the same time we can make the same process to calculate the resistance of the fat, then

$A_m = (0.18)\pi r^2 = (0.18)\pi (12/2*10^{-2})^2$

$A_m = 2.0357*10^{-3}m^2$

The resistance of the fat would be,

$R_f = \rho \frac{L}{A}$

$R_f = \frac{25*(0.4)}{2.0357*10^{-3}}$

$R_f = 4912.3\Omega$

Then the total resistance in a set as the previously writen, i.e, in parallel is:

$R=\frac{R_mR_f}{R_m+R_f}$

$R = \frac{(560.70)(4912.3)}{4912.3+560.70}$

$R = 502.62\Omega$

We can here apply Ohm's law, then

$I= \frac{V}{R}$

$I = \frac{1.5}{502.62}$

$I = 2.984*10^{-3}A$

$I = 2.984mA$

3 0

4 years ago

In a cyclic process, a gas performs 123 J of work on its surroundings per cycle. What amount of heat, if any, transfers into or

Aleks04 [339]

Answer:

123 J transfer into the gas

Explanation:

Here we know that 123 J work is done by the gas on its surrounding

So here gas is doing work against external forces

Now for cyclic process we know that

$\Delta U = 0$

so from 1st law of thermodynamics we have

$dQ = W + \Delta U$

$dQ = W$

so work done is same as the heat supplied to the system

So correct answer is

123 J transfer into the gas

4 0

3 years ago

A construction worker pushes a wheelbarrow with a total mass of 50.0kg. What is the acceleration of the wheelbarrow if the net f

Zarrin [17]

Did you try googling it lol thats what i do if its a problem like that. sometimes there are websites that answer it you just have to look really hard

5 0

3 years ago

What is moment? What are the two factors which affect moment

IgorC [24]

Explanation:

moment is an expression involving the product of a distance and physical quantities.

-the size of force applied.

-the perpendicular distance from the pivot to the line of action of the force

7 0

4 years ago

What is an electron?<br><br><br> (it’s D lol)

kupik [55]

Answer:

Explanation:

4 0

3 years ago