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ozzi
3 years ago
13

What is the number of significant digits in the measurement 34.000 m?

Physics
2 answers:
12345 [234]3 years ago
7 0
The answer is d.5 your welcome
Galina-37 [17]3 years ago
7 0

Answer:

it's d there you go

Explanation:

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3 years ago
A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine
liq [111]

(a) 24.6 Nm

The torque produced by the net thrust about the center of the circle is given by:

\tau = F r

where

F is the magnitude of the thrust

r is the radius of the wire

Here we have

F = 0.795 N

r = 30.9 m

Therefore, the torque produced is

\tau = (0.795 N)(30.9 m)=24.6 N m

(b) 0.035 rad/s^2

The equivalent of Newton's second law for a rotational motion is

\tau = I \alpha

where

\tau is the torque

I is the moment of inertia

\alpha is the angular acceleration

If we consider the airplane as a point mass with mass m = 0.741 kg, then its moment of inertia is

I=mr^2 = (0.741 kg)(30.9 m)^2=707.5 kg m^2

And so we can solve the previous equation to find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{24.6 Nm}{707.5 kg m^2}=0.035 rad/s^2

(c) 1.08 m/s^2

The linear acceleration (tangential acceleration) in a rotational motion is given by

a=\alpha r

where in this problem we have

\alpha = 0.035 rad/s^2 is the angular acceleration

r = 30.9 m is the radius

Substituting the values, we find

a=(0.035 rad/s^2)(30.9 m)=1.08 m/s^2

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3 years ago
Help me please....
snow_tiger [21]

Answer:

1) Time period

2) amplitude

3) Hertz or hz

4) Noise

5) frequency

6) infrasonic and ultrasonic

7) solid liquid and gas

8) A man

9) energy

10)1 vibration per minute

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3 years ago
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