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hodyreva [135]
1 year ago
14

1) A satellite in orbit around Earth is in uniform circular motion. What is the angle between the velocity vector and accelerati

on vector at any given point on the orbit?(1 point)
0º
0º

45º
45º

180º
180º

90º

2) A hammer thrower spins a hammer in a circle. What happens when the centripetal force drops to 0?(1 point)

The centripetal force cannot drop to 0.
The centripetal force cannot drop to 0.

The hammer continues in the circular motion.
The hammer continues in the circular motion.

The hammer drops straight to the ground.
The hammer drops straight to the ground.

The hammer flies off at a tangent to its circular path.
3) A bike racer follows a circular indoor track, racing at constant speed. In what direction is their acceleration, and why?(1 point)

In the direction of motion, accelerating their speed.
In the direction of motion, accelerating their speed.

Counter to the direction of motion, keeping her speed constant.
Counter to the direction of motion, keeping her speed constant.

Inward to the center of the track, the direction of the force needed to keep her on this path.
Inward to the center of the track, the direction of the force needed to keep her on this path.

Outward, the direction she would go if not constrained by the track.
4)A diagram shows the velocity vector for an object in uniform circular motion. Why is the vector tangential to the circle?(1 point)

The vector approximates the curved path at that point.
The vector approximates the curved path at that point.

The vector indicates the direction of the force on the object.
The vector indicates the direction of the force on the object.

The vector shows the path the object would follow if the net force acting on it stopped.
The vector shows the path the object would follow if the net force acting on it stopped.

The vector shows how the object pulls against the centripetal force.
5) A satellite is in uniform circular motion around the Moon. What happens to the direction of the acceleration vector during one full orbit?(1 point)

The acceleration vector always points in the direction of motion.
The acceleration vector always points in the direction of motion.

The acceleration vector always points outward.
The acceleration vector always points outward.

The acceleration vector oscillates back and forth.
The acceleration vector oscillates back and forth.

The acceleration vector always points inward.
Physics
1 answer:
artcher [175]1 year ago
6 0

Answer:90

Explanation: bc i looked it up

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You've been tired and lethargy what are two possible reasons?
dybincka [34]

Explanation:

physical exertion.

lack of physical activity.

lack of sleep.

being overweight or obese.

periods of emotional stress.

boredom.

grief.

taking certain medications, such as antidepressants or sedatives.

5 0
3 years ago
The process by which the gene in the nucleotide suddenly changes its position is called.
Ksenya-84 [330]

Mutation is the process by which the gene in the nucleotide suddenly changes its position

Any change in the structure of a gen or in the usual DNA sequence of a cell is called mutation. It can be caused by mistakes during cell division when the DNA is copied or by the exposure to DNA damaging agents in the environment like UV light or cigarette smoke, and may be transmitted to subsequent generations.

A mutation is a permanent alteration of the nucleotide sequence of an organism, virus or other genetic elements.

There are three types of mutations:

  • Base substitutions
  • Deletions
  • Insertions

<h3>What is DNA?</h3>

The Deoxyribonucleic acid, also called DNA, is the hereditary material that carries genetic information for the development and functioning of humans and almost all other organisms. DNA is made of nucleotides.

Learn more about DNA at brainly.com/question/16099437

#SPJ4

8 0
2 years ago
A 52.0-kg sandbag falls off a rooftop that is 22.0 m above the ground. The collision between the sandbag and the ground lasts fo
sergiy2304 [10]

Answer:

F = 7,916,955.0N

Explanation:

According to newtons second law

Force = mass * acceleration

Given

mass = 52.0kg

distance S = 22.0m

time t = 17.0 ms = 0.017s

We need to get the acceleration first using the formula;

S = ut+ 1/2at²

22 = 0 + 1/2 a(0.017²)

22 = 0.0001445a

a = 22/0.0001445

a = 152,249.13m/s²

The magnitude of the average force exerted will be;

F = ma

F = 52 * 152,249.13

F = 7,916,955.0N

4 0
3 years ago
If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?
vovikov84 [41]

Complete Question

In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?

Answer:

The speed of the helicopter is u  =  7.73 \  m/s

Explanation:

From the question we are told that

   The height at which he let go of the brief case is  h =  130 m  

    The  time taken before the the brief case hits the water is  t =  6 s

Generally the initial speed of the  briefcase (Which also the speed of the helicopter )before the man let go of it is  mathematically evaluated using kinematic equation as

      s = h+  u t +  0.5 gt^2

Here s  is the distance covered by the bag at sea level which is zero

      0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>    0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>   u  =  \frac{-130 +  (0.5 * 9.8 *  6^2) }{6}

=>   u  =  7.73 \  m/s

     

7 0
3 years ago
A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a
VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

r_1 = 45 sin15 \hat i + 45 cos15 \hat j

r_1 = 11.64 \hat i + 43.46\hat j

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

r_2 = 30 cos15\hat i + 30 sin15 \hat j

r_2 = 28.98\hat i + 7.76 \hat j

now the displacement of the boat is given as

d = r_2 - r_1

d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)

d = 17.34 \hat i - 35.7 \hat j

so the magnitude is given as

d = \sqrt{17.34^2 + 35.7^2}

d = 39.7 km

4 0
3 years ago
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