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hodyreva [135]
1 year ago
14

1) A satellite in orbit around Earth is in uniform circular motion. What is the angle between the velocity vector and accelerati

on vector at any given point on the orbit?(1 point)
0º
0º

45º
45º

180º
180º

90º

2) A hammer thrower spins a hammer in a circle. What happens when the centripetal force drops to 0?(1 point)

The centripetal force cannot drop to 0.
The centripetal force cannot drop to 0.

The hammer continues in the circular motion.
The hammer continues in the circular motion.

The hammer drops straight to the ground.
The hammer drops straight to the ground.

The hammer flies off at a tangent to its circular path.
3) A bike racer follows a circular indoor track, racing at constant speed. In what direction is their acceleration, and why?(1 point)

In the direction of motion, accelerating their speed.
In the direction of motion, accelerating their speed.

Counter to the direction of motion, keeping her speed constant.
Counter to the direction of motion, keeping her speed constant.

Inward to the center of the track, the direction of the force needed to keep her on this path.
Inward to the center of the track, the direction of the force needed to keep her on this path.

Outward, the direction she would go if not constrained by the track.
4)A diagram shows the velocity vector for an object in uniform circular motion. Why is the vector tangential to the circle?(1 point)

The vector approximates the curved path at that point.
The vector approximates the curved path at that point.

The vector indicates the direction of the force on the object.
The vector indicates the direction of the force on the object.

The vector shows the path the object would follow if the net force acting on it stopped.
The vector shows the path the object would follow if the net force acting on it stopped.

The vector shows how the object pulls against the centripetal force.
5) A satellite is in uniform circular motion around the Moon. What happens to the direction of the acceleration vector during one full orbit?(1 point)

The acceleration vector always points in the direction of motion.
The acceleration vector always points in the direction of motion.

The acceleration vector always points outward.
The acceleration vector always points outward.

The acceleration vector oscillates back and forth.
The acceleration vector oscillates back and forth.

The acceleration vector always points inward.
Physics
1 answer:
artcher [175]1 year ago
6 0

Answer:90

Explanation: bc i looked it up

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Which of the following scenarios would be optimal for obtaining a date from radioactive decay using these isotopes: 87Rb, 147Sm,
REY [17]

Answer:

a) 238U, 40K and 87Rb, b)   235U and to a lesser extent 40K , c)  he 235U,

d) possibility is 14C , e)this period would be ideal for 14C , f) 14C should be used since it is the one with the least average life time, even though the measurements must be very careful

Explanation:

One of the applications of radioactive decay is the dating of different systems.

To do this, the quantity of radioactive material in a meter is determined and with the average life time, the time of the sample is found.

Let's write the half-life times of the given materials

87Rb T ½ = 4.75 1010 years

147Sm T ½ = 1.06 1011 years

235U = 7,038 108 years

238U = 4.47 109 years

40K = 1,248 109 years

14C = 5,568 103 years

we already have the half-life of the different elements given

a) meteors. As these decomposed in the formation of the solar system, their life time is around 3 109 to 5 109 years, so it is necessary to look for elements that have a life time of this order, among the candidates we have 238U, 40K and 87Rb if these elements were at the moment of the formation of these meteors, there must still be rations in them, instead elements 14C already completely adequate

b) rock. The formation period is 4.20-108 years, therefore one of the most promising elements is 235U and to a lesser extent 40K since it is more abundant in rocks. The other elements with higher life times have not decayed and therefore will not give a true value and the 14C is completely decayed

c) volcanic ash. Formation time 6107 years, the only element that has the possibility of having a count is the 235U, the others have a life time so long that they have not decayed and the 14C is complete, unbent

d) scarp of an earthquake formation time 5 101 years, The only one that has any possibility is 14C even when it has declined very little, all the others, you have time to long that has not decayed

e) INCA excavation. The time of this civilization is about 10000 to 500 years (104 to 5 102 years), we see that this period would be ideal for 14C since it has some period of cementation, the others have not decayed

f) Tree in Blepharitis. 14C should be used since it is the one with the least average life time, even though the measurements must be very careful because of a period of disintegration. We have such a long time that they have not decayed

8 0
3 years ago
A hollow cylinder with an inner radius of 5 mm and an outer radius of 26 mm conducts a 4-A current flowing parallel to the axis
bearhunter [10]

Answer:

B = 38.2μT

Explanation:

By the Ampere's law you have that the magnetic field generated by a current, in a wire, is given by:

B=\frac{\mu_o I_r}{2\pi r}     (1)

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

r: distance from the center of the cylinder, in which B is calculated

Ir: current for the distance r

In this case, you first calculate the current Ir, by using the following relation:

I_r=JA_r

J: current density

Ar: cross sectional area for r in the hollow cylinder

Ar is given by  A_r=\pi(r^2-R_1^2)

The current density is given by the total area and the total current:

J=\frac{I_T}{A_T}=\frac{I_T}{\pi(R_2^2-R_1^2)}

R2: outer radius = 26mm = 26*10^-3 m

R1: inner radius = 5 mm = 5*10^-3 m

IT: total current  = 4 A

Then, the current in the wire for a distance r is:

I_r=JA_r=\frac{I_T}{\pi(R_2^2-R_1^2)}\pi(r^2-R_1^2)\\\\I_r=I_T\frac{r^2-R_1^2}{R_2^2-R_1^2}  (2)

You replace the last result of equation (2) into the equation (1):

B=\frac{\mu_oI_T}{2\pi r}(\frac{r^2-R_1^2}{R_2^2-R_1^2})

Finally. you replace the values of all parameters:

B=\frac{(4\pi*10^{-7}T/A)(4A)}{2\PI (12*10^{-3}m)}(\frac{(12*10^{-3})^2-(5*10^{-3}m)^2}{(26*10^{-3}m)^2-(5*10^{-3}m)^2})\\\\B=3.82*10^{-5}T=38.2\mu T

hence, the magnitude of the magnetic field at a point 12 mm from the center of the hollow cylinder, is 38.2μT

8 0
2 years ago
How many watt hours will 3-155amp hour 12 volt batteries wired in a parallel configuration produce?
Ede4ka [16]

Answer:

B 5580 W•hr

Explanation:

A Watt is a Volt times an Amp

3(12 V(155 A•hr)) = 5580 W•hr

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3 years ago
Which of the following is not the one of the influencing factors when it comes to body type
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The shanghai maglev train is capable of reaching speeds of up to 350km h-1 what is the speed in m/h
LenaWriter [7]

Answer:

The shanghai maglev train is capable of reaching speeds of up to 217.48 in mph

217.48 mph

Explanation:

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3 years ago
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