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frez [133]
3 years ago
9

The direction of deflection of an electron beam in a magnetic field can be determined by which of the following?

Physics
1 answer:
amid [387]3 years ago
4 0

Answer:

Right Hand Rule

Explanation:

When a charged particle travels in a magnetic field, it experiences a force whose magnitude is given by:

F=qvBsin\theta

where

q is the charge of the particle

v is the velocity

B is the magnetic field strength

\theta is the angle between the directions of v and B

The direction of the force can be determined by using the Right Hand Rule, as follows:

- index finger: this should be put in the direction of the velocity

- middle finger: this should be put in the direction of the magnetic field

- thumb: this will give the direction of the force -> however, for a negative charge (as the electron) the direction must be reversed, so it will be opposite.

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Answer:

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Explanation:

P = 50 N

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Resultant is given by

R=\sqrt{P^2+Q^2+2PQ\cos\theta}\\\Rightarrow R=\sqrt{50^2+30^2+2\times 50\times 30\times \cos45^{\circ}}\\\Rightarrow R=74.31\ \text{N}

Angle of resultant

\phi=\tan^{-1}\dfrac{Q\sin\theta}{P+Q\cos\theta}\\\Rightarrow \phi=\tan^{-1}\dfrac{30\times \sin45^{\circ}}{50+30\cos45^{\circ}}\\\Rightarrow \phi=16.59^{\circ}

Magnitude of the resultant is 74.31\ \text{N}

Direction of the resultant is 16.59^{\circ}

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