2 years ago

What is the balance of S8+Br2=S3Br7

Chemistry

1 answer:

GalinKa [24]2 years ago

8 0

Answer:

3S₈ + 28Br₂ => 8S₃Br₇

Explanation:

Start with either sulfur (S) or bromine (Br) and balance ...

3S₈ + Br₂ => 8S₃Br₇ or S₈ + 7/2Br₂ => S₃Br₇

Balance the remaining reactant ...

3S₈ + 56/2Br₂ => 8S₃Br₇

Remove fractions by multiplying by the fraction's denominator

2(3S₈ + 56/2Br₂ => 8S₃Br₇) => 6S₈ + 56Br₂ => 16S₃Br₇

Reduce to smallest whole number ratio => standard equation at STP ...

3S₈ + 28Br₂ => 8S₃Br₇

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