Answer:
Doing associative brainstorming
Allow all members who have an opinion or comment to contribute
You cannot criticize someone or there judgment on a topic
Always encourage someone if they need help with something and give input
Let everyone talk and share there solutions
Explanation:
Overall it’s good to do the things I have listed above because it can help you in planning.
Answer:
See explaination
Explanation:
We can describe Aspiration Effect as a phenomenon of providing an allowance for the release of air from the mold cavity during the metal pouring.
See the attached file for detailed solution of the given problem.
Answer:
0.577
Explanation:
Answer:
Explanation:
Parameters given:
Angle = 30°
Mass of block = 5kg
Velocity = 6 m/s
Time = 4s
Frictional force is given in terms of Normal force as:
F = uN
Where u = coefficient of frictional force
N = normal force
Frictional force is given as:
F = mgsinθ
Normal force is given as:
N = mgcosθ
Coefficient of friction is therefore given as:
mgsinθ = u * mgcosθ
=> u = sinθ / cosθ
u = tanθ
u = tan(30°)
u = 0.577
Answer:
The limits of the hole size are;
The maximum limit of the hole diameter 0.255
The minimum limit of the hole diameter = 0.245
Explanation:
Tolerance is a standardized form of language that can be used to define the intended 'tightness' or 'clearance' degree between mating parts in a mechanical assembly process and in metal joining processes such as welding and brazing processes
In tolerancing, the size used in the description of a part is known as the nominal size while allowable variation of the nominal size that will still allow the part to function properly is known as the tolerance
A tolerance given in the form ±P is known as bilateral tolerancing, with the value being added to or subtracted from the nominal size to get the maximum and minimum allowable limits of the dimensions of the nominal size
Therefore;
The given nominal dimension of the hole diameter = 0.250
The bilateral tolerance of the dimension, = ±0.005
Therefore;
The maximum limit of the diameter of the hole = 0.250 + 0.005 = 0.255
The minimum limit of the diameter of the hole = 0.250 - 0.005 = 0.245