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Angelina_Jolie [31]
3 years ago
15

A large heat pump should upgrade 5 MW of heat at 85°C to be delivered as heat at 150°C. Suppose the actual heat pump has a COP o

f 2.5. How much power is required to drive the unit? For the same COP, how high a high temperature would a Carnot heat pump have, assuming the same low T?

Engineering
1 answer:
AysviL [449]3 years ago
7 0

Answer:

W=2 MW

Explanation:

Given that

COP= 2.5

Heat extracted from 85°C  

Qa= 5 MW

Lets heat supplied at 150°C   = Qr

The power input to heat pump = W

From first law of thermodynamics

Qr= Qa+ W

We know that COP of heat pump given as

COP=\dfrac{Qr}{W}

2.5=\dfrac{5}{W}

2.5=\dfrac{5}{W}

W=2 MW

For Carnot heat pump

COP=\dfrac{T_2}{T_2-T_1}

2.5=\dfrac{T_2}{T_2-(273+85)}

2.5 T₂ -  895= T₂

T₂=596.66 K

T₂=323.6 °C

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Answer:

V1=5<u>ft3</u>

<u>V2=2ft3</u>

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Explanation:

PART A:

the volume of each state is obtained by multiplying the mass by the specific volume in each state

V=volume

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since the PV ^ n is constant we can equal the equations of state 1 and state 2

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3 years ago
How can we calculate the speed of the output gear in a simple gear train? Explain with the help of an example.
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Answer:

N_3=\dfrac{T_1}{T_3}N_1

Explanation:

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Speed\ of\ gear 1=N_1

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A small lake with volume of 160,000 m^3 receives agricultural drainage waters that contain 150 mg / L total dissolved solids (TD
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Answer:

Explanation:

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