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Lilit [14]
3 years ago
14

A person wearing a shoulder harness can survive a car crash if the acceleration is smaller than -300 m/s . assuming constant acc

eleration how far must the front end of the car collapse if 2 it crashes while going 101 km/hr?
Physics
1 answer:
mars1129 [50]3 years ago
3 0

To solve this problem, we use the equation:

<span>d = (v^2  - v0^2) / 2a</span>

 

where,

d = distance of collapse

v0 = initial velocity = 101 km / h = 28.06 m / s

v = final velocity = 0

a = acceleration = - 300 m / s^2

 

d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)

<span>d = 1.31 m</span>

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4 0
3 years ago
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3. A cat walks 0.220km North, then 0. 120 km South in a time of 400 seconds. whats the displacement and average velocity?
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Answer:

The rate at which velocity changes with respect to a change in time is called. acceleration.

Explanation:

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Definition of AM and Fm Wave? in your own word
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Answer:

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8 0
3 years ago
A mother and her 35.0 -kg child are riding an escalator to the third level of a shopping mall. If the child's gravitational pote
notka56 [123]

The increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.

<h3>What is gravitational potential energy?</h3>

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

The potential energy increases by 3773 J

PE₂-PE₁=mg(h₂-h₁)

3773 J = 35.0 × 9.81 × (h₂-h₁)

(h₂-h₁) = 10.98

Case 2 ;

ΔPE =?

ΔPE=mg(h₂-h₁)

ΔPE=56.0 × 9.81 ×10.98

ΔPE=6031.97 J.

Hence, the increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.

To learn more about the gravitational potential energy, refer;

brainly.com/question/3884855#SPJ1

#SPJ1

8 0
1 year ago
A boat, whose speed in still water is 2.50 m/s, must cross a 285-m wide river and arrive at a point 118m upstream from where it
son4ous [18]

The figure shows the arrangement of system

The velocity of boat can be resolved in to two

     Horizontal component  = vcos θ = 2.50 cos 45 = 1.768 m/s

     Vertical component  = vsin θ = 2.50 sin 45 = 1.768 m/s

   Due to horizontal component the boat arrive arrives upstream,

           Total horizontal velocity =  1.768 - Vr, where Vr is the velocity of river.

  Total time taken to cross the river = width of river/ Vertical component of velocity

                         t = 285/1.768 = 161.20 seconds

So 118 meter is traveled at a velocity of 1.768-Vr in 161.20 seconds

That is           118 = (1.768-Vr)*161.20

                     1.768 - Vr =0.732

                         Vr = 1.036 m/s

So velocity of river flow =1.036 m/s

4 0
3 years ago
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