Answer:
Explanation:
q = Charge of proton = 
v = Velocity of proton = 
c = Speed of light = 
B = Magnetic field = 0.00687 T
= Angle = 
Magnetic force is given by
The magnetic force acting on the proton is
Answer:
<em>a. q=450 c
</em>
<em>b. E=675 J
</em>
Explanation:
<u>Direct Current (DC)
</u>
It's the flow of electric charges in one direction driven by a constant voltage circuit. The intensity of the current flow is computed as
Where q is the constant flow of charge in time t
The energy of an element providing Voltage V, current I during a time t is
a. The charge can be computed by solving the first equation for q
b. The energy transferred by the battery is
Answer:
2.01
Explanation:
First, we need to find the centripetal acceleration.
We're given that the merry go round rotates 1 revolution in 2.09 seconds. Converting to rpm, we know that it rotates 30 revolution per minute
Now this speed gotten in rpm will be converted to m/s, to ease the calculation
30 rpm = πdN/60 m/s
30 rpm = (3.142 * 4 * 30)/60
30 rpm = 377.04/60
30 rpm = 6.284 m/s
a(c) = v²/r
a(c) = 6.284²/2
a(c) = 39.49 / 2
a(c) = 19.74 m/s²
F = ma
F = 50 * 19.74
F = 987 N
Also, Normal Force, F(n) =
F(n) = mg
F(n) = 50 * 9.81
F(n) = 490.5
We then use this to find the coefficient of static friction, μ
μ = F/F(n)
μ = 987 / 490.5
μ = 2.01
Answer:
h = r- R with r = ∛ (G M T² / 4π²)
Explanation:
As the satellite interacts with the Earth, let's use the law of universal gravitation
F = G m M / r²
Let's write Newton's second law
F = m a
a = v2 / r
G m M / r² = m v² / r
G M / r = v²
r = G M / v²
Let's work on satellite speed, counting speed, so we use uniform speed expressions
v = d / t
Let's look for the distance it travels in a complete orbit and its time is equal to one (1) day since the satellite is geosynchronous
d = 2π r
t = T = 1 day (24h / 1day) (3600s / 1h) = 86400 s
v = 2 π R / T
Let's calculate
r = G M (T / 2π r)²
r = G M T² / 4π² r²
r³ = G M T² / 4π²
r = ∛ (G M T² / 4π²)
This distance (r) is measured from the center of the earth, let's get the height (h) from the planet's surface
r = R + h
h = r- R
Answer: D. 36.8 N
Explanation:
F = ma = (2.45 kg)(15 m/s2) = 36.8 N
