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3 years ago

For the function f(x)=2x+1 and g(x)=3x-2, find (f-g)(4)

Mathematics

1 answer:

icang [17]3 years ago

4 0

Answer:

-5

Step-by-step explanation:

Here is how you solve this problem:

First, you set it up like this: 2x+1-3x+2

Second:You are finding f(4) and g(4) so you just plug in 4 for both problems:

2(4)+1-3(4)-2= 9-14= -5

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In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find: AC, if CD = 6√2 in.

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Answer:

AC = 12 units.

Step-by-step explanation:

Δ ACD is right-angled. ( as CD ⊥ AB).

cos 45° = CD / AC = 6√2 / AC

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AC = 6√2 / 1 /√2

= 6√2 *√2

= 6 * 2

= 12 (answer)

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sineoko [7]

Step-by-step explanation:

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3 years ago

Law of sines: 2.2 units 2.4 units 3.0 units 3.3 units

Arada [10]

Answer:

$RS=2.4\ units$

Step-by-step explanation:

<em>The complete question is </em>

What is the length of line segment RS? Use the law of sines to find the answer. Round to the nearest tenth.

see the attached figure to better understand the problem

step 1

Find the measure of angle S

Applying the law of sines

$\frac{QS}{sin(R)}=\frac{QR}{sin(S)}$

substitute the given values

$\frac{3.1}{sin(80^o)}=\frac{2.4}{sin(S)}$

Solve for sin(S)

$sin(S)=\frac{sin(80^o)}{3.1}(2.4)$

$S=sin^{-1}[sin(80^o)}{3.1}(2.4)]$

$S=49.68^o$

step 2

Find the measure of angle Q

Remember that the sum of the interior angles in any triangle mut b equal to 180 degrees

$m\angle Q+m\angle R+m\angle S=180^o$

substitute the given values

$m\angle Q+80^o+49.68^o=180^o$

$m\angle Q+129.68^o=180^o$

$m\angle Q=180^o-129.68^o$

$m\angle Q=50.32^o$

step 3

Find the length of segment RS

Applying the law of sines

$\frac{QS}{sin(R)}=\frac{RS}{sin(Q)}$

substitute the given values

$\frac{3.1}{sin(80^o)}=\frac{RS}{sin(50.32^o)}$

$RS=\frac{3.1}{sin(80^o)}{sin(50.32^o)}$

$RS=2.4\ units$

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3 years ago