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Levart [38]
3 years ago
7

Which process allows green plants to control the amount of water stored in their leaves ? I forgot!

Physics
1 answer:
Natalija [7]3 years ago
6 0
It is photosynthesis
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Kepler's second law: as a planet moves around its orbit, it sweeps out ______areas in ______ times.
natali 33 [55]
<span>Kepler's second law: as a planet moves around its orbit, it sweeps out  EQUAL areas in EQUAL times.

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3 years ago
A friend claims that throwing a baseball up towards the school roof illustrates gravitational potential energy transforming into
Cloud [144]

Answer:

The Statement is wrong because the reverse is the case as it is the  kinetic energy that is being transformed to gravitational potential energy.

Explanation:

As your friend throws  the baseball into the air the ball gains an initial velocity (u) and this makes the Kinetic energy to be equal to

                    KE = \frac{1}{2} mu^2

Here  m is the mass of the baseball

       Now as this ball moves further upward the that velocity it gained reduce due to the gravitational force and this in turn reduces the kinetic energy of the ball and this kinetic energy lost is being converted to gravitational potential energy which is mathematically represented as (m×g×h)

as energy can not be destroyed but converted to a different form according to the first law of thermodynamics

Looking a the formula for gravitational potential energy we see that the higher the ball goes the grater the gravitational potential energy.

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3 years ago
Most of the currents identified have a circular shape. This is because as the air and water move between the equator to the pole
Morgarella [4.7K]
I believe it is true . Somebody correct me if I’m wrong!
5 0
2 years ago
A pure substance that cannot be broken down into any other substances by chemical or physical means is a (n)
dem82 [27]
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3 years ago
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An object is 50 cm from a converging lens with a focal length of 40 cm . A real image is formed on the other side of the lens, 2
Leno4ka [110]

Answer:

d) -4.0

Explanation:

The magnification of a lens is given by

M=-\frac{q}{p}

where

M is the magnification

q is the distance of the image from the lens

p is the distance of the object from the lens

In this problem, we have

p = 50 cm is the distance of the object from the lens

q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct

Also, q is positive since the image is real

So, the magnification is

M=-\frac{200 cm}{50 cm}=-4.0

7 0
3 years ago
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