Answer:
i) SF:
ii) BM : 
Explanation:
Let's take,
Making y the subject of formula, we have :

For shear force (SF), we have:
This is the area of the diagram.

The shear force equation =
For bending moment (BM):


The bending moment equation =

Answer:
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is the volume of the sample when the water content is 10%.
<u>Explanation:</u>
Given Data:

First has a natural water content of 25% =
= 0.25
Shrinkage limit, 

We need to determine the volume of the sample when the water content is 10% (0.10). As we know,
![V \propto[1+e]](https://tex.z-dn.net/?f=V%20%5Cpropto%5B1%2Be%5D)
------> eq 1

The above equation is at
,

Applying the given values, we get

Shrinkage limit is lowest water content

Applying the given values, we get

Applying the found values in eq 1, we get


Answer:
the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
Explanation:
Given that;
depth 1 = 71 ft
depth 2 = 10 ft
pressure p = 17 psi = 2448 lb/ft²
depth h = 71 ft - 10 ft = 61 ft
we know that;
p = P_air + yh
where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )
so we substitute;
p = 2448 + ( 49.3 × 61 )
= 2448 + 3007.3
= 5455.3 lb/ft³
= 37.88 psi
Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi