I = 48 mA, R = 1125 2. What is Vs ?

Calculate the pressure drop in a duct (measured by a differential oil manometer) if the differential height between the two flui

Burka [1]

Answer:

The pressure drop is 269.7N/m^2

Explanation:

∆P = ∆h × rho × g

∆h = 3.2cm = 3.2/100 = 0.032m, rho = 860kg/m^3, g = 9.8m/s^2

∆P = 0.032×860×9.8 = 269.7N/m^2

6 0

2 years ago

In a 5V system if you were asked to take one input HIGH and another LOW what would you do (i.e. where would you connect them)?

dangina [55]

Answer:

HIGH from the supply voltage

LOW from ground

Explanation:

The answer depends on the kind of system and the purpose of the signal. But for practical reasons, in a DIGITAL system where 5V is HIGH and 0 V is LOW, 5 volts can be taken from the supply voltage (usually the same as high, BUT must be verified), and the LOW signal from ground.

If the user has a multimeter, it must be set to continuous voltage on 0 to 20 V range. Then place the probe in the ground of the circuit (must be a big copper area). Finally leave one probe in the circuit ground and place the other probe in some test points to identify 5 v.

4 0

3 years ago

balandron [24]

Answer:

a) 0.42

b) Independent

c) 30%

d) 0.88

Explanation:

Person chooses Chicken's item : 70% = 0.7

Person chooses fish's item : 30% = 0.3

Visits in which he orders Afghani Chicken = 60% = 0.6

a)

Probability that he goes to KARIM and orders Afghani Chicken:

P = 0.7 * 0.6 = 0.42

b)

Two events are said to be independent when occurrence of one event does not affect the probability of the other event's occurrence. Here the person orders Afghani Chicken regardless of where he visits so the events are independent.

c)

P = 0.30 because he orders Afghani Chicken regardless of where he visits.

d)

Let A be the probability that he goes to KARIM:

P(A) = 0.7 * ( 1 - 0.6 ) = 0.28

Let A be the probability that he orders Afghani Chicken:

P(B) = 0.3 * 0.6 = 0.18

Let C be the probability that he goes to KARIM and orders Afghani chicken:

= 0.7 * 0.6 = 0.42

So probability that he goes to KARIM or orders Afghani Chicken or both:

P(A) + P(B) + P(C) = 0.28 + 0.18 + 0.42 = 0.88

4 0

3 years ago

What are the main causes of injuries when using forklifts?

astra-53 [7]

Answer:

overturns

Explanation:

6 0

3 years ago

Read 2 more answers

What is the correct expression of the internal moment in segment AB? A 10-ft-long cantilever beam is fixed at end A (x = 0). A u

Komok [63]

Answer:

Option A

Question (in proper order)

What is the correct expression of the internal moment in segment AB? A 10-ft-long cantilever beam is fixed at end A (x = 0). A uniform distributed load of 2 kip/ft is applied between A and B (x = 6 ft). A downward 10-kip force is applied at B, and an upward 8-kip force is applied at end C (x = 10 ft). In addition, a clockwise couple moment of 40 kip-ft is exerted at the free end C. What is the correct expression of the internal moment in segment AB?

(First Diagram attached below)

$a. -x^{2} + 14x -56 kip.fit \\b. -x^2 + 14x kip.fit\\c. -x^2\\d. -x^{2} + 14x -24\\e. -x^{2} + 24\\f. -x^{2} - 56$

Explanation:

(From the second diagram attached below)

Note that

Moment of a force is the product of the force and the perpendicular distance

sum of horizontal forces, ∑Fx = 0 (that is sum of forces acting towards left = sum of forces acting towards right)

that is zero in this case

Sum of vertical forces, ∑Fy = 0 ( that is sum of forces acting upward = sum of forces acting downward)

Total upward force = Total downward force

Ay + 8 = 10 + 2 x 6

where Ay is the force acting at the fixed end

Ay + 8 = 10 + 12

Ay = 22 - 8

Ay = 14 Kip ( force is measured in kip while distance is measured in ft)

Sum of clockwise moment = Sum of anticlockwise moment

let us assume a counterclockwise moment about point A = Ma

8 x 10 + Ma = 40(counterclockwise moment) + (2 x 6) x 3(total uniform force assumed to act at the middle of the 6ft length) + 10 x 6

80 + Ma = 40 + 36 + 60

Ma = 136 - 80

Ma = 56 kip-fit

(From the third diagram attached below)

Consider a section of beam AB from A to X and of distance x fit

let the counterclockwise moment about Xx section be Mx

if we take moment about the Xx section

then

summation of moment about the Xx section ∑Mxx = 0

hence,

Mx + 56 + {(2 * x)[total of the uniform force] * x/2[acting at the middle point of the x ft distance]} = Ay * x

Mx + 56 + 2x * x/2 = 14 * x

Mx + 56 + x^2 = 14x

Mx = $-x^2 + 14x - 56$ kip-ft

8 0

2 years ago