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blondinia [14]
4 years ago
7

Air at 7°C enters a turbojet engine at a rate of 16 kg/s and at a velocity of 220 m/s (relative to the engine). Air is heated in

the combustion chamber at a rate 15,000 kJ/s, and it leaves the engine at 427°C. Determine the thrust produced by this turbojet engine.
Engineering
1 answer:
Readme [11.4K]4 years ago
6 0

Answer:

F=14.05 KN

Explanation:

Now from first law for open system

h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+w

In Turbojet net work out put is zero because ,power produce by turbine is consumed by compressor.

So w=0

Given mass flow rate =16 kg/s

V_1=220 m/s

Heat input Q=15000 KW  (Q=937.5 KJ/kg)

h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}

1.005\times (273+70)+\dfrac{220^2}{2000}+937.5=1.005\times (273+427)+\dfrac{V_2^2}{2000}

So V_2=1098.1 m/s

So thrust

F=\dot{m_a}(V_2-V_1)

F=16(1098.32-220)

F=14.05 KN

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If a signal is transmitted at a power of 250 mWatts (mW) and the noise in the channel is 10 uWatts (uW), if the signal BW is 20M
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Answer:

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  • common brick / magnesia : 1019 °C
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Explanation:

The thermal resistance (R) of a layer of thickness d given in °C·m²·h/kJ is ...

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So, the total thermal resistance is ...

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__

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_____

<em>Comment on temperatures</em>

Most temperatures are rounded to the nearest degree. We wanted to show the small temperature drop across the steel plate, so we showed the inside boundary temperature to enough digits to give the idea of the magnitude of that.

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