Answer:
38.67 N
Explanation:
v = Final velocity = 40 m/s
u = Initial velocity
m = Mass of ball = 0.145kg
s = Displacement of ball = 3 m
Equation of motion
F=ma
∴ Average force that a baseball pitcher's hand exerts on the ball is 38.67 N
Answer:
momentum
Explanation:
when something starts rolling momentum keeps it going.
<span>If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field.
it depends on the gravitational force of attraction of earth and air resistance.
if we are neglecting air resistance, the max.horizontal distance is according to this formulae,
V0/2 * sin (2theta)
where V0 is the initial velocity
theta is the angle with x axis and the projection.
There are a number of ways that you could find a horizontally displaced object. You could for example just look.</span>
