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klasskru [66]
3 years ago
9

Hurryyyyy pleaseeeee!!!!!

Physics
1 answer:
kolbaska11 [484]3 years ago
4 0

Answer: 2.2x10^4

Explanation: in a adiabatic process pV^y = constant.

So V2=3V1 and p2 = p1 / 3^1.67 = 2.2x10^4 Pa

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Which equation can correctly express the relation between force, acceleration, and mass?
Roman55 [17]

Hi there!

\large\boxed{\text{a) F = m * a}}

According to Newton's Second Law, force is calculated with the formula:

F = m × a, where:

F = force (N)

m = mass (kg)

a = acceleration (m/s²)

7 0
3 years ago
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Ball A is allowed to fall and strike ball B. Assume that all of ball A's energy is transferred to ball B at point I, and that th
Alika [10]

Answer:

Explanation:

If no Energy is lost ( either as Sound energy or any other energy) the total energy of ball A equals the total energy of ball B

Therefore the Kinetic Energy of Ball B equals the Total Energy of Ball A minus the Potential Energy of Ball A

K. E = T. E - P.E

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4 years ago
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How are mass and weight different? how does gravity affect mass and weight
m_a_m_a [10]
Mass is the amount of matter in an object whereas weight is the force of gravity acting on the mass of an object. Different planets exert a different force of gravity on an object-meaning that an object's weight will change depending on the force of gravity acting on it, but it's mad will remain unchanged.
8 0
3 years ago
Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?
tester [92]

Answer: 40\ N/C

Explanation:

Given

Magnitude of charge is q=0.5\ C

Force experienced is F=20\ N

Electric field intensity is the electrostatic force per unit charge

\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C

Thus, the electric field intensity is 40\ N/C

6 0
3 years ago
On a planet where g = 10.0 m/s2 and air resistance is negligible, a sled is at rest on a rough inclined hill rising at 30°. The
Cloud [144]

Answer:

Explanation:

a is the acceleration

μ is the coefficient of friction

Acceleration of the object is given by

a = g (\sin  \theta -\mu \cos \theta)\\\\=10( \sin 30 - 0.4 \cos 30)\\\\=10(0.5-0.3464)\\\\=1.54m/s^2

Velocity at the bottom

v^2=u^2+2as\\\\u=0\\\\v^2=2as\\\\=2*1.54*8\\\\=24.576\\\\v=4.96m/s

after travelling 4m , its velocity becomes 0

a=\frac{v^2-u^2}{2s}

a=\frac{0-u^2}{2s}

a=\frac{-(-4.96)^2}{2*4} \\\\=-3.075m/s^2

Coefficient of kinetic friction

μ = F/N

=\frac{ma}{mg} \\\\=\frac{3.075}{10} \\\\=0.31

Therefore, the Coefficient of kinetic friction is 0.31

8 0
3 years ago
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