<u>Answer:</u>
Pressure exerted = 500 Pa
<u>Explanation:</u>
The formula for pressure is as follows:
In this case,
Force applied = 100N
Area = 40cm × 50cm = 2000cm² = 2000 × 10⁻⁴ = 0.2m²
Substituting these values into the formula:
Pressure = 
⇒ Pressure = 500 Pa
A)
5m/s^2
(12m/s-2m/s)
__________ = 5m/s^2
2s
Answer:
A is true
Explanation:
Other all are wrong I guess
Answer:
Power= 0.5hp = 375W
T = 3hrs = 10800s
Power = Work done/ Time
Work = Power * Time = 375 * 10800 = 4050000J
Answer:
The necessary information is if the forces acting on the block are in equilibrium
The coefficient of friction is 0.577
Explanation:
Where the forces acting on the object are in equilibrium, we have;
At constant velocity, the net force acting on the particle = 0
However, the frictional force is then given as
F = mg sinθ
Where:
m = Mass of the block
g = Acceleration due to gravity and
θ = Angle of inclination of the slope
F = 5×9.81×sin 30 = 24.525 N
Therefore, the coefficient of friction is given as
24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479
μ × 42.479 N= 24.525 N
∴ μ = 24.525 N ÷ 42.479 N = 0.577
