I believe there are two correct answers, and those answers are A and D
Answer:
The acceleration is 2.2 m/s^2
Explanation:
In the attached image, we can see the free body diagram. And using the second law of Newton it will be possible to find the acceleration of the box.
<h3><u>Solution</u><u>:</u></h3>
- Distance (d) = 112 m
- Time (t) = 4 seconds
- Let the speed be v.
- We know, speed = Distance / Time
- Therefore, v = d/t
or, v = 112 m ÷ 4 s = 28 m/s
<h3><u>Answer</u><u>:</u></h3>
<u>The </u><u>speed </u><u>of </u><u>the</u><u> </u><u>cheetah</u><u> </u><u>is </u><u>2</u><u>8</u><u> </u><u>m/</u><u>s.</u>
The water outflow in 30 secs through 200 mm of the capillary tube is mathematically given as
<h3>What is the water outflow in 30 secs through 200 mm of the capillary tube?</h3>
Generally, the equation for Rate of flow of Liquid is mathematically given as
$$
Where dP is pressure difference r is the radius
is the viscosity of water
L is the length of the pipe
In $30s the quantity that flows out of the tube
In conclusion, the quantity that flows out of the tube
Read more about the flows rate
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Answer:
Work out = 28.27 kJ/kg
Explanation:
For R-134a, from the saturated tables at 800 kPa, we get
= 171.82 kJ/kg
Therefore, at saturation pressure 140 kPa, saturation temperature is
= -18.77°C = 254.23 K
At saturation pressure 800 kPa, the saturation temperature is
= 31.31°C = 304.31 K
Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.
Thus, = = 171.82 kJ/kg
We know COP of heat pump
COP =
=
= 6.076
Therefore, Work out put, W =
= 171.82 / 6.076
= 28.27 kJ/kg