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Gnom [1K]
3 years ago
6

How do you think the gravitational force between two objects will change if the distance between the objects is doubled

Physics
1 answer:
USPshnik [31]3 years ago
4 0
We Know, F = Gm₁m₂ / r²
When, distance is doubled, it would be:
F' = Gm₁m₂ / (2r)²
F' = Gm₁m₂ / 4r

So, we can see, Force has decreased by 4 times.

Hope this helps!
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What's the concept of mass ?
Marat540 [252]
Masa is a concept that identifies that magnitude of a physical nature that allows indicating the amount of matter in a body. Within the International System , its unit is the kilogram ( kg . ) 
6 0
3 years ago
The table below describes some processes in which food is changed as it travels through the digestive system.
satela [25.4K]

Answer:

processes 1,3, and 4

Explanation:

i think

3 0
3 years ago
The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration, skidding to a comp
Ber [7]

Answer: -6.80\ ms^{-2}

Explanation:

We know that the formula for acceleration is given by:

a=\dfrac{v-u}{t} , where v = Final velocity

u= Initial velocity

Given :  The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration.

i.e. u=   110 km/h =\dfrac{110\times1000}{3600}\approx35.6\ m/s  [∵  1 km= 100 meters and 1 hour = 3600 seconds]

v=  0  m/s ( At brake , final velocity becomes 0)

t=4.5 seconds  

Substitute all the values in the formula , we get

a=\dfrac{0-30.56}{4.5}\approx-6.80\ ms^{-2}

Hence, the average acceleration of the car during braking is -6.80\ ms^{-2}.

5 0
3 years ago
A current of 3.60A flows for 15.3s through a conductor. Calculate the number of electrons that pass through a point in the condu
Artyom0805 [142]

3.60 A = 3.60 coulombs of charge per second

(3.60 Coul/sec) x (15.3 sec) = 55.08 coulombs of charge

1 coulomb of charge is carried by 6.25 x 10^18 electrons

Number of electrons =

               (55.08 Coul) x (6.25 x 10^18 e/coul) = <em>3.4425 x 10^20 electrons</em>


7 0
4 years ago
Mercury has one of the lowest specific heats. This fact added to its liquid state at most atmospheric temperatures make it effec
UNO [17]

The specific heat of mercury is 149.4 J/(kgK)

Explanation:

When a substance is supplied with an amount of energy Q, its temperature increases according to the equation:

\Delta T=\frac{Q}{mC_s}

where

\Delta T is the increase in temperature

m is the mass of the sample

C_s is its specific heat capacity

For the sample of mercury in this problem we have

Q = 275 J

m = 0.450 kg

\Delta T = 4.09 K

Therefore, by re-arranging the equation we find the mercury's specific heat:

C_s = \frac{Q}{m\Delta T}=\frac{275}{(0.450)(4.09)}=149.4 J/(kgK)

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

5 0
4 years ago
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