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Rina8888 [55]
3 years ago
13

Two brothers, Frank and Dion, are on roller skates and standing still when they push off from one another. Frank's mass is 103.4

kg. Dion's mass is 51.6 kg. After they push off, Frank has a velocity of -7 m/s. What will Dion's velocity be?
Physics
1 answer:
tigry1 [53]3 years ago
3 0
Around -3.5 ( might not be completely right ) Frank has a greater mass to he has a low velocity at first, Dion is around half of his weight so he doesn’t have to use as much force to get more than Frank
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Calculate the speed of body moving a distance of 320km in 4h
ololo11 [35]
Convert km to m. -> 320km=320000 m
Convert hours to seconds -> 4 hrs=14400 s
Divide the distance by time because v=d/t
320000/14400=22.22 m/s
6 0
2 years ago
What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperatu
Firlakuza [10]

Answer: 9.0 atm

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=3.0atm\\V_1=150mL\\P_2=?mmHg\\V_2=50mL

Putting values in above equation, we get:

3.0\times 150mL=P_2\times 50mL\\\\P_2=9.0atm

Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm

5 0
3 years ago
Which has more volume a liter of a quart?
shtirl [24]
Answer 4, liter
it’s not the same and it does describe volume
8 0
3 years ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 17601760 × 103 seconds (ab
Yuliya22 [10]

Answer:

The value is a_r  = 3.81 *10^{-3} m/s^2

Explanation:

Generally the moon's radial acceleration is mathematically represented as

a_r  =  r *  w^2

Here w is the angular velocity which is mathematically represented as

w =\frac{2 \pi }{ T}

substituting 1760 * 10^3 \ seconds for T(i.e the period of the moon ) we have

w =\frac{2  * 3.142 }{  1760 * 10^3}

=> w = 3.57 *10^{-6} \  rad/s

From the question r(which is the radius of the orbit ) is evaluated as

r =  R + H

substitute 3.60 * 10^6 m for R and 295.0 * 10^6  \  m H

       r =  295.0 * 10^6   +3.60 * 10^6

=>   r =  2.986 *10^{8} \  m

So

    a_r  =   2.986 *10^{8} *  ( 3.57 *10^{-6} )^2

      a_r  = 3.81 *10^{-3} m/s^2

4 0
3 years ago
I throw a ball off the edge of a 15.0m cliff. If I threw it horizontally at 8.0 m/s, how much time did it take to fall?
pickupchik [31]
Just ignore the horizontal component 

if you have a vertical displacement of 15m, 0ms^1 initial velocity, end velocity is ignored, we know the acceleration due to gravity as 9.81ms^2 so we can work out the time using SUVAT

S=15
U=0
V=?
A=9.81
T=?

S=UT + 0.5 AT^2

UT=0

therefore,

S=0.5AT^2

rearrange to:

T=SQR (2S/A)

T = 1.75 seconds
 


3 0
3 years ago
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