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3 years ago

Consider the balanced equation below. 4NH3 + 3O2 2N2 + 6H2O What is the mole ratio of NH3 to N2?

Chemistry

2 answers:

vladimir1956 [14]3 years ago

3 0

Is go be 4x=7 so when you see yo thing pick the 2nd one it's go be b

Marina86 [1]3 years ago

3 0

Explanation:

A chemical reaction equation that contains same number of atoms on both reactant and product side is known as a balanced equation.

For example, $4NH_{3} + 3O_{2} \rightarrow 2N_{2} + 6H_{2}O$

Here, number of nitrogen atoms on both reactant and product side is 4.

Number of hydrogen atoms on both reactant and product side is 12.

Number of oxygen atoms on both reactant and product side is 6.

Since, there are 4 moles $NH_{3}$ and 2 moles of $N_{2}$ .

Therefore, we can conclude that mole ration of $NH_{3}$ to $N_{2}$ is 4:2 which is equal to 2:1.

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The depletion of ozone (O3) in the stratosphere has been a matter of great concern among scientists in recent years. It is belie

Deffense [45]

Answer: Nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

Explanation:

To calculate the number of moles, we use the equation

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For ozone:

Given mass of ozone = 0.827 g

Molar mass of ozone = 48 g/mol

Putting values in above equation, we get:

$\text{Moles of ozone}=\frac{0.827g}{48g/mol}=0.0172mol$

For nitric oxide:

Given mass of nitric oxide = 0.635 g

Molar mass of nitric oxide = 30.01 g/mol

Putting values in above equation, we get:

$\text{Moles of nitric oxide}=\frac{0.635g}{30.01g/mol}=0.0211mol$

For the given chemical equation:

$O_3+NO\rightarrow O_2+NO_2$

By Stoichiometry of the reaction:

1 mole of ozone reacts with 1 mole of nitric oxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitric oxide

As, given amount of nitric oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ozone is considered as a limiting reagent because it limits the formation of product.

Amount of excess reagent (nitric oxide) left = 0.0211 - 0.0172 = 0.0039 moles

By Stoichiometry of the reaction:

1 mole of ozone produces 1 mole of nitrogen dioxide.

So, 0.0172 moles of ozone will react with = $\frac{1}{1}\times 0.0172=0.0172moles$ of nitrogen dioxide

Now, calculating the mass of nitrogen dioxide from equation 1, we get:

Molar mass of nitrogen dioxide = 46 g/mol

Moles of nitrogen dioxide = 0.0172 moles

Putting values in equation 1, we get:

$0.0172mol=\frac{\text{Mass of nitrogen dioxide}}{46g/mol}\\\\\text{Mass of nitrogen dioxide}=0.7912g$

Hence, nitric oxide is the limiting reagent. The number of moles of excess reagent left is 0.0039 moles. The amount of nitrogen dioxide produced will be 0.7912 g.

8 0

3 years ago

Three of Louis Pasteur discovery

konstantin123 [22]

Pasteurization, vaccines against antrax and rabies, discovered the germ fermentation

7 0

3 years ago

Formula for Sodium Hydrogen Carbonate NaHCO3? or Na2HCO3?

yan [13]

NaHCO3 is the right answer

8 0

3 years ago

Which type of bonding is characterized by overlapping orbitals that allow outer electrons of atoms to move about freely througho

Sonja [21]

Answer:

D metallic

Explanation:

The chemical bonding which rises from electrostatic attractive force between the conduction electrons and the positively charged metal ions is called metallic bonding.

It is sharing of the free electrons among the structure of the positively charged ions which are known as cations.

In this type of bonding, these free electrons freely move in the crystal mattice of the metal.

The bonding accounts for properties of metals, such as ductility, strength, electrical and thermal conductivity and resistivity and luster.

6 0

3 years ago

A solution of LiCl in water has XLiCl = 0.0800. What is the molality? A solution of LiCl in water has XLiCl = 0.0800. What is th

Kay [80]

Answer:

mol LiCl = 4.83 m

Explanation:

GIven:

Solution of LiCl in water XLiCl = 0.0800

Mol of water in kg = 55.55 mole

Find:

Molality

Computation:

mole fraction = mol LiCl / (mol water + mol LiCl)

0.0800 = mol LiCl / (55.55 mol + mol LiCl)

0.0800 mol LiCl + 4.444 mol = mol LiCl

mol LiCl - 0.0800 mol LiCl = 4.444 mol

0.92 mol LiCl = 4.444 mol

mol LiCl = 4.83 m

7 0

3 years ago