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DENIUS [597]
3 years ago
13

Consider the balanced equation below. 4NH3 + 3O2 2N2 + 6H2O What is the mole ratio of NH3 to N2?

Chemistry
2 answers:
vladimir1956 [14]3 years ago
3 0
Is go be 4x=7 so when you see yo thing pick the 2nd one it's go be b
Marina86 [1]3 years ago
3 0

Explanation:

A chemical reaction equation that contains same number of atoms on both reactant and product side is known as a balanced equation.

For example, 4NH_{3} + 3O_{2} \rightarrow 2N_{2} + 6H_{2}O

Here, number of nitrogen atoms on both reactant and product side is 4.

Number of hydrogen atoms on both reactant and product side is 12.

Number of oxygen atoms on both reactant and product side is 6.

Since, there are 4 moles NH_{3} and 2 moles of N_{2}.

Therefore, we can conclude that mole ration of NH_{3} to N_{2} is 4:2 which is equal to 2:1.

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Determine the molar concentration of na+ and po4 3- in a 2.25 M Na3 PO4 solution
muminat

Answer:

A. The concentration of Na^+ in the solution is 6.75 M.

B. The concentration of PO4^3- in the solution is 2.25 M.

Explanation:

We'll begin by writing the balanced dissociation equation for Na3PO4.

This is illustrated below:

Na3PO4 will dissociate in solution as follow:

Na3PO4(aq) —> 3Na^+(aq) + PO4^3-(aq)

Thus, from the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+ and 1 mole of PO4^3-

A. Determination of the concentration of Na+ in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of Na^+.

Therefore, 2.25 M Na3PO4 solution will produce = (2.25 x 3) /1 = 6.75 M Na^+.

Therefore, the concentration of Na^+ in the solution is 6.75 M

B. Determination of the concentration of PO4^3- in 2.25 M Na3PO4 solution.

This can be obtained as follow:

From the balanced equation above,

1 mole of Na3PO4 produce 1 mole of PO4^3-

Therefore, 2.25 M Na3PO4 solution will also produce 2.25 M PO4^3-.

Therefore, the concentration of PO4^3- in the solution is 2.25 M.

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Explanation:

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