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3 years ago

Static, sliding and rolling are types of friction true or false

Physics

2 answers:

Evgen [1.6K]3 years ago

7 0

Its true because of all its friction durng movement

Marina CMI [18]3 years ago

4 0

True because friction happens when two things are rubbed against each other and it creates force and sliding something vigorously against something else can create force.

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In a college homecoming competition, eighteen students lift a sports car. While holding the car off the ground, each student exe

Nata [24]

Answer:

Explanation:

Given

Each student exert a force of $F=400 N$

Let mass of car be m

there are 18 students who lifts the car

Total force by 18 students $F=18\times 400=7200 N$

therefore weight of car $W=7200$

mass of car $m=\frac{W}{g}$

$m=\frac{7200}{9.8}=734.69 kg$

(b) $7200 N \approx 1618.624\ Pound-force$

$734.69 kg\approx 1619.71 Pounds$

6 0

3 years ago

When you measure something in meters cubed, you are measuring ____.

Shalnov [3]

I think your answer is volume

7 0

3 years ago

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After turning off the television, you approach it. As you get close, but not touching it, the hairs on your arm start to stand u

Amanda [17]

The answer is D) induction.

6 0

3 years ago

Read 2 more answers

HELP PLEASE

4vir4ik [10]

Recall this kinematic equation:

a = $\frac{Vi+Vf}{Δt}$

This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).

a is the acceleration.

Vi is the initial velocity.

Vf is the final velocity.

Δt is the amount of elapsed time.

Given values:

Vi = 0 m/s (the car starts at rest).

Vf = 25 m/s.

Δt = 10 s

Substitute the terms in the equation with the given values and solve for a:

a = $\frac{0+25}{10}$

7 0

3 years ago

Read 2 more answers

One cycle of the power dissipated by a resistor ( R = 800 Ω R=800 Ω) is given by P ( t ) = 60 W , 0 ≤ t < 5.0 s P(t)=60 W, 0≤

OLga [1]

Answer:

42.5W

Explanation:

To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

We need to calculate the average power dissipated by the 800\Omega resistor.

Our values are given by:

$P(t)=60 W, 0\leq t$

$P(t)=25 W, 5.0\leq t$

Aplying the values to the equation we have:

$Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}$

$Power_{avg} = \frac{60(5-0)+25(10-5)}{(5-0)+(10-5)}$

$Power_{avg} = 42.5W$

5 0

3 years ago