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3 years ago

Which is an example of potential en

Physics

2 answers:

SIZIF [17.4K]3 years ago

8 0

a yoyo in someones hand is an example of potential energy

bogdanovich [222]3 years ago

7 0

A yo-yo in someone’s hand

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The 400-turn primary coil of a step-down transformer is connected to an ac line that is 120 V rms. The secondary coil voltage is

KengaRu [80]

Explanation:

The given data is as follows.

$V_{1}$ = 120 V, $V_{2}$ = 6.50 V

$N_{1}$ = 400, $N_{2}$ = ?

Formula to calculate the number of turns in secondary coil are as follows.

$\frac{N_{1}}{N_{2}} = \frac{V_{1}}{V_{2}}$

Putting the given values into the above formula as follows.

$\frac{N_{1}}{N_{2}} = \frac{V_{1}}{V_{2}}$

$\frac{400}{N_{2}} = \frac{120}{6.50}$

$N_{2}$ = 21.66

= 22 (approx)

Thus, we can conclude that number of turns in the secondary coil are 22.

3 0

3 years ago

A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an

anyanavicka [17]

Answer:

The value of tangential acceleration $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

The value of radial acceleration $\alpha_{r} = 80 \frac{m}{s^{2} }$

Explanation:

Angular acceleration = 50 $\frac{rad}{s^{2} }$

Radius of the disk = 0.8 m

Angular velocity = 10 $\frac{rad}{s}$

We know that tangential acceleration is given by the formula $\alpha_{t} =$ $r \alpha$

Where r = radius of the disk

$\alpha$ = angular acceleration

⇒ $\alpha_{t} =$ 0.8 × 50

⇒ $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

This is the value of tangential acceleration.

Radial acceleration is given by

$\alpha_{r} = \frac{V^{2} }{r}$

Where V = velocity of the disk = r $\omega$

⇒ V = 0.8 × 10

⇒ V = 8 $\frac{m}{s}$

Radial acceleration

$\alpha_{r} = \frac{8^{2} }{0.8}$

$\alpha_{r} = 80 \frac{m}{s^{2} }$

This is the value of radial acceleration.

7 0

4 years ago

You hear the sound of the firing of a distant cannon 6.9 s after seeing the flash. how far are you from the cannon? (assume 343

EastWind [94]

Let's call d the distance of the cannon from us. We see the flash first, then after 6.9 s we hear the sound. The flash arrives to us traveling at speed of light, which is $c=3 \cdot 10^8 m/s$ , while the sound travels at speed $v=343 m/s$ . Since the magnitude of the speed of light is much much larger than the speed of sound, we can assume that the flash arrives at our location instantaneously after the firing.
Then we can say that the sound wave covers a distance d traveling at speed v in a time of t=6.9 s. Since it is a uniformly linear motion, the distance covered by the sound wave is
$d=vt=(343 m/s)(6.9 s)=2367 m$
So, this is the distance of the cannon from us.

6 0

3 years ago

About how long passess between high tides

Virty [35]

about 12 hours I think, since there are two high tides per day

6 0

4 years ago

Copper has a specific heat of 0.09 cal/g x C . How much change in temperature would the addition of 8373 cal of heat have on a 5

neonofarm [45]

<h3>Answer:</h3>

172.92 °C

<h3>Explanation:</h3>

Concept being tested: Quantity of heat

We are given;

Specific heat capacity of copper as 0.09 cal/g°C
Quantity of heat is 8373 calories
Mass of copper sample as 538.0 g

We are required to calculate the change in temperature.

In this case we need to know that the amount of heat absorbed or gained by a substance is given by the product of mass, specific heat capacity and change in temperature.

That is, Q = m × c × ΔT

Therefore, to calculate the change in temperature, ΔT we rearrange the formula;

ΔT = Q ÷ mc

Thus;

ΔT = 8373 cal ÷ (538 g × 0.09 cal/g°C)

= 172.92 °C

Therefore, the change in temperature will be 172.92 °C

3 0

3 years ago