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wlad13 [49]
3 years ago
10

What is the Volume of the salt solution? ​

Chemistry
1 answer:
hammer [34]3 years ago
3 0
<h3>Answer:</h3>

61.3 mL

<h3>Explanation:</h3>

From the data given;

  • Mass of volumetric flask is 109.1 g
  • Mass of salt is 5.01 g
  • Mass of Volumetric flask and salt is 113.5 g
  • Mass of volumetric flask and salt solution is 170.4 g
  • Mass of salt solution is 61.3 g

We are required to calculate the volume of salt solution;

We need to know the relationship between density, mass and volume of a solution.

Density = Mass ÷ Volume

Therefore, given mass and density we can find the volume.

Rearranging the formula;

Volume = Mass ÷ density

Assuming the density of salt solution is 1 g/mL

Then;

Volume = Mass of the salt solution ÷ density of the salt solution

             = 61.3 g ÷ 1 g/mL

             = 61.3 mL

Therefore, the volume of the salt solution is 61.3 mL

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Write the condensed electron configurations for the Ca atom. Express your answer in condensed form as a series of orbitals. For
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Answer:

[Ar] 4s²

Explanation:

Ca is the symbol for Calcium. It is the 20th element and it has 20 electrons.

The full electronic configuration for calcium is given as;

1s²2s²2p⁶3s²3p⁶4s²

The condensed electronic configuration is given as;

[Ar] 4s²

6 0
3 years ago
is the approximate relation celsius = 1/2 fahrenheit a better approximation at higher or lower temperatures?
kirill115 [55]

Answer : The approximate relation Celsius = 1/2 Fahrenheit is a better approximation at higher temperatures

Explanation :

The formula for Celsius to Fahrenheit conversion is

C = (F-32) \times \frac{5}{9}

At lower temperature the value that needs to be subtracted (32) is large enough as a result the approximation "celsius = 1/2 fahrenheit " does not seem valid.

For example, 50 F is 10°C.

(50 - 32) \times \frac{5}{9} = 10 C

This is almost 1/5 of Fahrenheit temperature.

But at higher temperatures , the value becomes insignificant and also the ratio  5/9 tend to be equal to 0.5.

For example, 2000 F is 1093°C

(2000 - 32) \times \frac{5}{9} = 1093 C

This is almost half of Fahrenheit temperature.

Therefore , the approximate relation Celsius = 1/2 Fahrenheit is a better approximation at higher temperatures

8 0
4 years ago
What is the Answer of the picture
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Answer: d

Explanation: I got it right

8 0
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A sample of urea contains 1.121 g of N, 0.161 g of H, 0.48 g of C, and 0.64 g of O. What is the empirical formula of urea?
dybincka [34]

Answer:

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Explanation:

5 0
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Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain
damaskus [11]

Answer:

Ka = ( [H₃O⁺] . [F⁻] ) / [HF]

Explanation:

HF is a weak acid which in water, keeps this equilibrium

HF (aq)  +  H₂O (l)  ⇄  H₃O⁺ (aq)  +  F⁻ (aq)      Ka

2H₂O (l)  ⇄  H₃O⁺ (l)  +  OH⁻ (aq)   Kw

HF is the weak acid

F⁻ is the conjugate stron base

Let's make the expression for K

K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]

K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]

K . [H₂O] = Ka

Ka, the acid dissociation constant, includes Kwater.

4 0
3 years ago
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