Answer:
The correct answer is - 1/4096.
Explanation:
In the starting, there is that the number of atoms is N
0
.
The number of half-lives in this case, = 300/ 25 = 12
After the first half-lives or 25 days, N
1
=
N
0
/2
the half life is that time where half of the sample had decay.
After the second half-life or 50 days, N
2
=
N
1
/2 =
N
0
/4
.
There is division by two the original amount, then after four times you divide four times for 2 that means that you divide by 2
^12 =4096
.
So the final amount remain is N
12
=
N
0
/4096 or 1/4096.
The sum of the percentage abundance of these two isotopes of the new synthetic element should be equal to 100. If we let x be the percent abundance of the second isotope, we have the equation, 43 + x = 100The value of x = 57
Reactivity.
All the others are examples of a physical property.
46. F the mouth.
Because the mouth works as the food smasher and with the addition of saliva the food will be softer to digest.
47. D The Weight
Because weight is mass times the acceleration of gravity and acceleration of gravity is different on moon 1.620 m/s^2.
48.G Two elements
Because compounds are made of two or more than two elements.
No It is not correct.
Correct oxidation number of hydrogen in NaH,H2 and H2S are:
- Let x be the Oxidation state of ’H’ by oxidation state rule.
x+1 =0 (Sodium has +1 Oxidation state )
x=−1
Therefore, -1 is oxidation number of Hydrogen in NaH.
- The oxidation number of an element's atom in its standard state is zero. As a result, the oxidation number for H2 is zero.
- The hydrogen oxidation number in H2 is +1. As a result, that hydrogen atom can be reduced to lower oxidation states of hydrogen, such as 0 and -1. However, because +1 is the highest oxidation state of hydrogen, the hydrogen atom cannot be reduced any further.
<h3>What is oxidation number?</h3>
In simple terms, the oxidation number is the number assigned to elements in a chemical combination. The oxidation number is the number of electrons that atoms in a molecule can share, lose, or gain when forming chemical bonds with atoms of a different element.
Learn more about oxidation number in:
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