Answer:
1.016 seconds
Explanation:
Let's bring out the parameters we were given in the question;
Rate constant k = 0.710 s^-1
Initial Concentration [A] = 0.820 M
Final concentration [A]o = 0.290 M
Time t = ?
Formular relating these parameters is given as;
ln[A] = ln[A]o − kt
Making t subject of interest, we have;
ln[A] - ln[A]o = -kt
kt = ln[A]o - ln[A]
t = (ln[A]o - ln[A]) / k
Substituting the values, we have;
t = ( ln(0.820) - ln(0.290) ) / 0.710
t = 0.7217 / 0.710
t = 1.016 seconds
Yes. Unsaturated hydrocarbon are more reactive than saturated hydrocarbons because it contains double bonds which can break and compounds can react with hydrogen.
Due to the double and triple bonds between carbon atoms in unsaturated hydrocarbons, which are weaker than the single bonds in saturated hydrocarbons due to the presence of weaker pi bonds, these unsaturated hydrocarbons are more reactive than single bonded carbon compounds and react more quickly when used in reactions.
For example, unsaturated hydrocarbons are used to make paint, lubricants, and insecticides, among other industrial products. They are utilised in numerous chemical reactions because they are reactive.
Therefore, Unsaturated hydrocarbon are more reactive than saturated hydrocarbons.
Learn more about Unsaturated hydrocarbon here:
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The answer is C, number of molecules.
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