HCl is a strong acid and so dissociates fully in water:
HCl(aq) --> H+(aq) + Cl-(aq)
Since there is a 1:1 mole ratio between HCl and H+ in this reaction, the number of moles of H+ = number of moles of HCl. The number of moles of HCl can be calculated as moles = mass/RMM = 0.80g / 36.5g/mol = 0.022mol.
Since 5.5 l of solution is made, the concentration of H+ is:
[H+] = 0.022mol / 5.5l = 0.004M. This can then be used to calculate pH through the equation pH = -log[H+] = -log(0.004) = 2.40
I just finished my assignment and this is what I got. Try to put these in your own words. (: Hope this helps.
Answer:
569K
Explanation:
Q = 3.5kJ = 3500J
mass = 28.2g
∅1 = 20°C = 20 + 273 = 293K
∅2 = x
c = 0.449
Q = mc∆∅
3500 = 28.2×0.449×∆∅
3500 = 12.6618×∆∅
∆∅ = 3500/12.6618
∆∅ = 276.4220
∅2 - ∅1 = 276.4220
∅2 = 276.4220 + ∅1
∅2 = 276.4220 + 293
∅2 = 569.4220K
∅2 = 569K
Answer:
7.28 mol
Explanation:
2 NaOH + H₂SO₄ = 2 H₂O + Na₂SO₄ -------------------(1)
mole fraction for the reaction is;
2 : 1 = 2 : 1
Number of moles of H₂SO₄ = 7.28 mol
1 mol of H₂SO₄ shall form 1 mole of Na₂SO₄
therefore,
7.28 mol of H₂SO₄ shall form 7.28 mole of Na₂SO₄
