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Elden [556K]
3 years ago
10

Which of the following hypotheses is written correctly?*

Physics
1 answer:
sweet [91]3 years ago
6 0

Answer:

4 Because Hypothesis sentence always have to be "If" and Then a "then"

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PH is the measure of the:
Morgarella [4.7K]

pH is the measure of the concentration of  hydrogen ions in a solution

5 0
3 years ago
PLEASE HELPPPPPPPP
LUCKY_DIMON [66]
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8 0
3 years ago
If a closed series circuit has a voltage of 12 V and R1 = 4 Ω and R2 = 2 Ω, what is the current running through R1 and R2?
Phantasy [73]
Total resistance=R1+ R2= 6Ω
Voltage=12v
Current =\frac{voltage}{resistance}
Current= 2A
In a series circuit, equal current passes through every resistance.
Answer is option A
7 0
3 years ago
A 1000kg car is rolling slowly across a level surface at 1 m/s heading twoards a group o fsmall innocent children. The doors are
Degger [83]

Answer:

The force required to push to stop the car is 288.67 N

Explanation:

Given that

Mass of the car, m = 1000 kg

Initial speed of the car, u = 1 m/s

The car and push on the hood at an angle of 30° below horizontal, \theta=30^{\circ}

Distance, d = 2 m

Let F is the force must you push to stop the car.

According work energy theorem theorem, the work done is equal to the change in kinetic energy as :

W=\dfrac{1}{2}m(v^2-u^2)F\times d=\dfrac{1}{2}m(v^2-u^2)

v = 0

Fd\ cos\theta=\dfrac{1}{2}m(u^2)      F=\dfrac{\dfrac{1}{2}m(u^2)}{d\ cos\theta}F=\dfrac{\dfrac{1}{2}\times 1000\times (1)^2}{2\ cos(30)}F = -288.67 N

The force required to push to stop the car is 288.67 N

3 0
3 years ago
Light shined through a single slit will produce a diffraction pattern. Green light (565 nm) is shined on a slit with width 0.210
kondor19780726 [428]

Answer:(a)9.685 mm

(b)4.184 mm

Explanation:

Given

Wavelength of light (\lambda )=565nm \approx 565\times 10^{-9}m

Width of slit(b)=0.210

(a)Width of central maximum located 1.80m from slit

=\frac{2\lambda L}{b}

=\frac{2\times 565\times 10^{-9}\times 1.8}{0.210\times 10^{-3}}

=9.685 mm

(b)Width of the first order bright fringe

Y_1=\frac{\lambda \times L}{b}

Y_1=\frac{565\times 10^{-9}\times 1.8}{0.210\times 10^{-3}}

Y_1=4.84mm

5 0
3 years ago
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