Question

A bowling ball has a mass of 6 kg. What happens to its momentum when its speed increases from 2m/s to 4 m/s?

Answer 1

Here, Initial momentum = mu = 6*2 = 12 Kg m/s
Final momentum = mv = 6*4 = 24 Kg m/s

In short, Your Answer would be Option C

Hope this helps!

Answer 2

Answer: The initial momentum is 12 kg m/s, and the final momentum is 24 kg m/s

Explanation:

Momentum is defined as the force that keeps the object moving.  It is also defined as the product of mass and velocity of an object.

Mathematically,

$p=m\times v$     .......(1)

where,

p = momentum of the bowling ball

m = mass of the bowling ball

v = velocity of the bowling ball

• Calculating the initial momentum:

We are given:

$m=6kg\\u=\text{Initial speed}=2m/s$

Putting values in equation 1, we get:

$p=6kg\times 2m/s\\\\p=12kg.m/s$

• Calculating the final momentum:

We are given:

$m=6kg\\u=\text{Final speed}=4m/s$

Putting values in equation 1, we get:

$p=6kg\times 4m/s\\\\p=24kg.m/s$

Hence, the initial momentum is 12 kg m/s, and the final momentum is 24 kg m/s