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Vedmedyk [2.9K]
2 years ago
8

Which statement accurately describes the motion of the object in the graph above over 10 seconds? Group of answer choices The ob

ject is at rest for 3 seconds and then decreases velocity to 1 cm/s for 3 seconds. The object is at rest for 4 seconds and then moves forward for 4 seconds at 1 cm/s. The object moves forward at 1 cm/s, stops, and then increases velocity to 2 cm/s. The object moves forward at 1 cm/s, stops, and then continues at the same velocity.

Physics
1 answer:
timurjin [86]2 years ago
7 0

Answer:

Object appears to move forward at 1 cm/sec, then the velocity drops to zero for 3 sec and then moves forward at 2 cm/sec     (11 - 3) / (10 - 6) = 2 cm/sec

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The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90
s2008m [1.1K]

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

6 0
3 years ago
A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform current density of 2.8 x 10^7A/m^2. The c
Mrac [35]

Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current densityJ=2.8\times10^{7}\ A/m^2

We need to calculate the current

Using formula of current density

J = \dfrac{I}{A}

I=J\timesA

Where, J = current density

A = area

I = current

Put the value into the formula

I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2

I=1.97=2.0\ A

Hence, The current is 2.0 A.

7 0
3 years ago
Define pressure snd state its SI units to​
Sophie [7]

Answer:

Pressure (P) is the amount of force applied perpendicular to the surface of an object per unit area. The SI unit of pressure is the pascal (Pa), which is equivalent to N/m^{2} (newtons per meter squared).

6 0
3 years ago
A zebra starts from rest and accelerates at 1.9 m/s how far has a zebra gone in five seconds
Maksim231197 [3]
To that multiply 1.9 by 5 to get 9.5.  The zebra has gone 9.5 m.
5 0
2 years ago
Here's a great everyday use of the physics described in Think about what subsequently happens to the ketchup, which is initially
balandron [24]

Answer:

Explanation:

The inertia of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle.

6 0
3 years ago
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