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Ugo [173]
3 years ago
15

When an object oscillating in simple harmonic motion is at its maximum displacement from the equilibrium position, which of the

following is true of the values of its speed and the magnitude of the restoring force?
Physics
1 answer:
expeople1 [14]3 years ago
5 0

Answer:

speed maximum

restoring force minimum

Explanation:

When the particle executing SHM is at its mean position or equilibrium position, then its velocity is maximum and the kinetic energy is also maximum. It is because the kinetic energy is proportional to the square of the velocity as velocity maximum then kinetic energy is also maximum.

The acceleration is minimum at the equilibrium position so the restoring force is also minimum t its equilibrium position.

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A particular wire has a resistivity of 6.47×10-8 Ωm and a cross-sectional area of 2.32 mm2. A length of this wire is to be used
PolarNik [594]

Using  the formula for power:

P = V^2 / R  

130 W = (9.00 V)^2 / R  

Solve for r:

R = 81/130

R = 0.623 ohms

Now solve for the length of wire:

R = rho L / A  

A must be in m^2 - 2.32 mm^2 * 1 m^2/10^6 mm^2 = 2.132x10^-6 m^2  

Now you have:

0.623 = (6.47x10^-8) L / (2.32x10^-6)  

L = 22.34 m (Round answer as needed.)

6 0
4 years ago
For which planet is the length of the plants day longer than the planets year
leonid [27]
I think Jupiter
Make as a abRainlist
6 0
3 years ago
A Carnot engine operates with a cold reservoir at a temperature of 474 K and a hot reservoir at a temperature of 628 K. What is
Zigmanuir [339]

Answer:

zero

Explanation:

A Carnot engine is an ideal engine in which the process is cyclic and reversible.

A Carnot engine is the engine whose efficiency is 100 % and the entropy in is equal to entropy out. That means the net change in entropy is zero.

5 0
3 years ago
11. A seesaw sits in static equilibrium. A child with a mass of 30 kg sits 1 m away from a pivot point. Another child sits 0.75
lora16 [44]

Answer:

<h2>40 kg</h2>

Explanation:

Find the diagram relating to the question for proper explanation of the question below.

Using the principle of moment

Sum of clockwise moments = Sum of anticlockwise moments

Moment = Force * perpendicular distance

For anti-clockwise moment:

Since the 30 kg moves in the anticlockwise direction according to the diagram

ACW moment = 30 * 1 = 30 kgm

For clockwise moment

If another child sits 0.75 m away from the pivot point on the opposite side, moment of the child in clockwise direction = M * 0.75 = 0.75M (M is the mass of the unknown child).

Equating both moments we have;

0.75M = 30

M = 30/0.75

M = 40 kg

The second child's mass is 40 kg

5 0
3 years ago
What is the deceleration of a bicycle that goes from 40m/s to 20m/s in 5 seconds
Alex Ar [27]

Answer:

-4 m/s^2

Explanation:

The acceleration of the bycicle is given by:

a=\frac{v-u}{t}

where

v = 20 m/s is the final velocity of the bike

u = 40 m/s is the initial velocity

t = 5 s is the time interval

Substituting numbers, we find

a=\frac{20 m/s-40 m/s}{5s}=-4 m/s^2

and the acceleration is negative, which means that the bycicle is slowing down.

5 0
3 years ago
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