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NISA [10]
3 years ago
14

The half-life of uranium-235 is 713 million years. Suppose a rock originally had 26 grams of uranium-235. A geologist had the ro

ck tested, and found that it now has only 3.25 grams of uranium-235.
Approximately how old is the rock?
Physics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

Answer:

<h3>2139 Million years</h3>

Explanation:

Half life of a material is the time required for the material to decay into half of initial amount.

initially there is 26 grams of uranium-235, and the final amount is 3.25 gram

                 ratio between initial and final amount = \frac{26}{3.25}  = \frac{1}{8}

now it is clear that the material have halved 3 times from initial condition

number of half lives passed = 3

number of half lives passed can also be found using the equation

                no of half lives = log_{2} \frac{R_{0} }{R}

where R_{0} is the initial amount of material and R is the final amount

∵ Number of half lives = log_{2} \frac{26 }{3.25}

                                      = 3

So, age of rock = half-life X number of half-lives passed

                          =713000000 X 3

                          = 2139000000

                          =2139 Million Years

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A 782-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satelli
Vadim26 [7]

Answer:

a) v = 5.59x10³ m/s

b) T = 4 h

c) F = 1.92x10³ N

Explanation:

a) We can find the satellite's orbital speed by equating the centripetal force and the gravitation force as follows:

F_{c} = F_{G}

\frac{mv^{2}}{r + h} = \frac{GMm}{(r + h)^{2}}

v = \sqrt{\frac{gr^{2}}{r+h}          

Where:

g is the gravity = 9.81 m/s²        

r: is the Earth's radius = 6371 km

h: is the satellite's height = r = 6371 km      

v = \sqrt{\frac{gr^{2}}{2r}} = \sqrt{\frac{gr}{2}} = \sqrt{\frac{9.81 m/s^{2}*6.371 \cdot 10^{6} m}{2}} = 5.59 \cdot 10^{3} m/s                                      

b) The period of its revolution is:

T = \frac{2\pi}{\omega} = \frac{2\pi (r + h)}{v} = \frac{2\pi (2*6.371 \cdot 10^{6} m)}{5.59 \cdot 10^{3} m/s} = 14322.07 s = 4 h

c) The gravitational force acting on it is given by:

F = \frac{GMm}{(r + h)^{2}}

Where:

M is the Earth's mass =  5.97x10²⁴ kg    

m is the satellite's mass = 782 kg

G is the gravitational constant = 6.67x10⁻¹¹ Nm²kg⁻²

F = \frac{GMm}{(r + h)^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}kg^{-2}*5.97 \cdot 10^{24} kg*782 kg}{(2*6.371 \cdot 10^{6} m)^{2}} = 1.92 \cdot 10^{3} N

I hope it helps you!

3 0
3 years ago
A small bulb is rated at 7.5 W when operated at 125 V. The tungsten filament has a temperature coefficient of resistivity α = 0.
alisha [4.7K]

To solve this problem we will apply the concepts related to resistance as a function of temperature, product of the relationship between the squared voltage and the power. Mathematically this is,

R = \frac{v^2}{P}

Here,

R = Resistance (At function of temperature)

v = Voltage

P = Power

Then we have,

R at 140°C (7 times room temperature),

R(140\°C) = \frac{125^2}{7.5}

R(140\°C) = 2083.33\Omega

The relationship between normal temperature and increased temperature would then be given by,

R(140\°C) = R(20\°C)(1 +\alpha (\Delta T))

R(140\°C) = R(20\°C)(1+(4.5*10^{-3})(140-20))

R(20\°C) = \frac{2083.33}{1.54}

R(20\°C) = 1352.81\Omega

Therefore the correct value of the group of answer is 1350

5 0
3 years ago
How would this affect the electrostatic force between them?
Alja [10]

The answer is increase

Explanation:

6 0
3 years ago
if a person with a mass of 70kg is standing on scale in an elevator when the cable snaps, what will the reading on the scale be
dybincka [34]

Answer:

The reading will be the same.

Explanation:

Mass does not depend upon anything and it remains the same anywhere. What changes is the weight of the body because it depends upon gravity and is different at different places.

Giving me the brainest will be helpful.

3 0
3 years ago
Suppose a cheetah running at a velocity of 5 m/s east slows down. After 15 seconds, the cheetah has reached a velocity of 25 m/s
Darina [25.2K]

Answer:

1.33m/s²

Explanation:

Given parameters:

Initial velocity  = 5m/s

Final velocity  = 25m/s

Time taken  = 15seconds

Unknown:

Acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time.

  Acceleration  = \frac{v - u}{t}  

  v is the final velocity

  u is the initial velocity

  t is the time taken

 So;

    Acceleration  = \frac{25 - 5}{15}    = 1.33m/s²

5 0
3 years ago
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