Ask question

Ask question

All categories

3 years ago

14

Bernie, whose mass is 70.0 kg, leaves a ski jump with a velocity of 21.0 m/s.What is Bernie’s momentum (kg*m/s) as he leaves the

ski jump?

1 answer:

zheka24 [161]3 years ago

6 0

Momentum = mass * velocity
Momentum = 70 * 21
Momentum = 1,470

Therefore, Bernie’s momentum was 1,470kg*m/s as he leaves the ski jump. :)

You might be interested in

Which of the following components of an electrical circuit is generally used to connect all other components?

Butoxors [25]

A a wire, a wire is connected between the positive and negative ends of the eletrical energy source and connects all the components in between.

3 0

3 years ago

How many significant digits are in the measurement 50.003010

Anastasy [175]

Hello There!

It is 6 sf

Hope This Helps You!
Good Luck :)

- Hannah ❤

6 0

2 years ago

Show that the energy of a magnetic dipole m in a magnetic field B is U--m B

Juli2301 [7.4K]

Answer:

showm

Explanation:

Consider a dipole having magnetic moment 'm' is placed in magnetic field $\vec{B}$ then the torque exerted by the field on the dipole is

$\tau = m\times B$

$\tau=mBsin\alpha$

Now to rotate the dipole in the field to its final position the work required to be done is

$U=\int \tau d\alpha$

$U=\int mBsin\alpha d\alpha$

$U= -mBcos\alpha$

$U=-\vec{m\times \vec{B}}$

Minimum energy mB is for the case when m is anti parallel to B.

Minimum energy -mB is for the case when m is parallel to B.

5 0

2 years ago

Is this true or false ethics deals with morals and values and can be measured and tested using the scientific method.

sammy [17]

This is false. Even though the first part is true, the second isn't because morals and values are simply widely accepted opinions that most humans have, and you can't test opinions with the scientific method, only facts!

3 0

2 years ago

Read 2 more answers

Force F → = (−8.0 N)iˆ + (6.0 N)jˆ acts on a particle with position vector r → = (3.0 m)iˆ + (4.0 m)jˆ. What are (a) the torque

disa [49]

Answer with Explanation:

We are given that

$F=-8\hat{i}+6\hat{j}$

$r=3\hat{i}+4\hat{j}$

a.We have to find the torque on the particle about the origin.

We know that

Torque= $\tau=r\times F=\begin{vmatrix}i&j&k\\3&4&0\\-8&6&0\end{vmatrix}$

By using the formula

$\tau=50\hat{k}$

b. $\mid \tau\mid =\mid F\mid \mid r\mid sin\theta$

$\mid F\mid=\sqrt{(-8)^2+(6)^2}=10$

$\mid r\mid=\sqrt{3^2+4^2}=5$

$\mid \tau\mid=\sqrt{(-50)^2}=50$

Substitute the values then we get

$50=10\times 5 sin\theta$

$sin\theta=\frac{50}{50}=1$

$sin\theta=sin90^{\circ}$

Because $sin90^{\circ}=1$

$\theta=90^{\circ}$

3 0

3 years ago