Answer:
10 hours earlier than regular train
Explanation:
In this case you are already giving the expression to be used which is:
S = D/t (1)
The problem is giving us the data of the speed of both trains, and we also know the distance between City A and B, which is 4000 km, therefore, we just need to solve for t in the above expression for both trains, and then, do the difference between their times and see how much earlier the express train arrives.
Solving for t, we have:
t = D/S (2)
For Train 1 (The regular):
t₁ = 4000 / 80
t₁ = 50 h
For Train 2 (Express):
t₂ = 4000 / 100
t₂ = 40 h
Now, as expected express train arrives earlier, now let's see how much:
T = t₁ - t₂
T = 50 - 40
<h2>
T = 10 h</h2><h2>
</h2>
Therefore, Express train arrives 10 hours earlier than regular train.
Hope this helps
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Answer:
Zero
Explanation:
Since momentum is a product of mass and velocity of an object, in this case when the object stops its final velocity is zero hence despite the magnitude of its mass, multiplied by zero the final momentum is equivalent to zero. However, in case after experiencing momentum its velocity reduces but doesn’t come to a rest, the momentum will have a value. For this question, the first case applies hence momentum value is zero.
The atomic mass of this question is 10.811