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snow_tiger [21]
3 years ago
5

An astronaunt takes am object to the moon where there is less gravity. Explain how the mass amd weight of an object on the moon

would compare to its mass and weight on Earth.
Physics
1 answer:
telo118 [61]3 years ago
6 0
Even tho the object is big it will still Float around like a balloon cause of the gravity in space that's why they hook the rocket-ship into the ground of space 
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A dog runs after a car. The car is travelling at an average speed of 5 m/s.
n200080 [17]

Answer:

<h2>The answer is 4 s</h2>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

where

d is the distance

v is the velocity

From the question we have

t =  \frac{20}{5}  \\

We have the final answer as

<h3>4 s</h3>

Hope this helps you

3 0
3 years ago
Read 2 more answers
6. A billiard ball traveling at 4.0 m/s has an elastic head-on collision with a billiard ball of equal mass
Yakvenalex [24]
Answer is C‼️.......................
7 0
3 years ago
Explain why gases are more compressible than solid
Oduvanchick [21]

Answer:

If we put pressure on a solid or a liquid, there is essentially no change in volume. ... The kinetic-molecular theory explains why gases are more compressible than either liquids or solids. Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.

Explanation:

7 0
3 years ago
Thermal energy transfers from a cup of tea at 350 K to the hand holding it. <br> A)True<br> B)False
Alexandra [31]

Answer:

true

Explanation:

it is an energy transfer

6 0
3 years ago
While driving, your car has an initial position of 3.2 m, an initial velocity of -8.4 m/s, and
KIM [24]

Answer:

The position of the car at t = 1.5 s is at -8.1625 meters

Explanation:

The initial position of the car is 3.2 meters

The initial velocity is -8.4 m/s

The constant acceleration is 1.1 m/s²

We need to find the final position of the car at the time t = 1.5 seconds

The displacement <em>s</em> = final position - initial position

s=ut+\frac{1}{2}at^{2}, where <em>u</em> is the initial velocity, <em>a</em> is the

constant acceleration and <em>t</em> is the time

So we can find the final velocity by using the rule:

final position - initial position = ut+\frac{1}{2}at^{2}

initial position = 3.2 meters , u = -8.4 m/s , a = 1.1 ²m/s , t = 1.5 s

Substitute these values in the rule

final position - 3.2 = (-8.4)(1.5)+\frac{1}{2}(1.1)(1.5)^{2}

final position - 3.2 = -12.6 + 1.2375

final position - 3.2 = -11.3625

add 3.2 for both sides

final position = -8.1625

<em>That means the car is at 8.1625 meters in opposite direction</em>

<em>The position of the car at t = 1.5 s is at -8.1625 meters </em>

4 0
3 years ago
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