Answer:
The work done will be 
Explanation:
The work equation is given by:
Where:
F is the force due to gravity (weight = mg)
x is the length of the ramp (3 m)
Now, the force acting here is the component of weight in the ramp direction, so it will be:
Therefore, the work done will be:
I hope it helps you!
Answer:
potential energy=mgh (weight × height)
m=20kg
g=9.8m/s2
h=8
20×9.8×8=1568
The potential energy is 1568J
Answer:
r= 2.17 m
Explanation:
Conceptual Analysis:
The electric field at a distance r from a charge line of infinite length and constant charge per unit length is calculated as follows:
E= 2k*(λ/r) Formula (1)
Where:
E: electric field .( N/C)
k: Coulomb electric constant. (N*m²/C²)
λ: linear charge density. (C/m)
r : distance from the charge line to the surface where E calculates (m)
Known data
E= 2.9 N/C
λ = 3.5*10⁻¹⁰ C/m
k= 8.99 *10⁹ N*m²/C²
Problem development
We replace data in the formula (1):
E= 2*k*(λ/r)
2.9= 2*8.99 *10⁹*(3.5*10⁻¹⁰/r)
r =( 2*8.99 *10⁹*3.5*10⁻¹⁰) / (2.9)
r= 2.17 m
Answer:
<em>Tangencial</em>.
Explanation:
El adjetivo empleado es<em> tangencial</em>, cuya longitud es diez caracteres. La <em>aceleración tangencial</em> es el componente del vector aceleración que es paralelo a la dirección del vector velocidad de un punto que se mueve sobre una circunferencia.
La aceleración tangencial tiene la función de cambiar la magnitud del vector aceleración.
