Answer:
(A). The order of the bright fringe is 6.
(B). The width of the bright fringe is 3.33 μm.
Explanation:
Given that,
Fringe width d = 0.5 mm
Wavelength = 589 nm
Distance of screen and slit D = 1.5 m
Distance of bright fringe y = 1 cm
(A) We need to calculate the order of the bright fringe
Using formula of wavelength


Put the value into the formula


(B). We need to calculate the width of the bright fringe
Using formula of width of fringe

Put the value in to the formula



Hence, (A). The order of the bright fringe is 6.
(B). The width of the bright fringe is 3.33 μm.
The units for mass are grams (g) and kilograms (kg)
the units for volume are millilitres (ml) and litres (l)
Q. The energy emitted from the sun is a product of ________.
A. Fusion
Answer:
The answer to the question is;
Based on their acceleration the rank of the satellites from largest to smallest is.
B >→ A >→ E >→ C >→ F >→ D.
Explanation:
Acceleration is given by 
Therefore the acceleration for each of the satellite is given by
Satellite A)
= 5.12 m/s²
Satellite B)
= 10.24 m/s²
Satellite C)
= 2.56 m/s²
Satellite D)
= 0.16 m/s²
Satellite E)
= 2.88 m/s²
Satellite F)
= 0.64 m/s²
Therefore in order of decreasing acceleration, from largest to smallest we have
Satellite B) > Satellite A) >Satellite E) >Satellite C)>Satellite F)>Satellite D).