Answer:
31.321 rad/s
Explanation:
L = Tube length
A = Area of tube
 = Density of fluid
 = Density of fluid
v = Fluid velocity
m = Mass = 
Centripetal force is given by

Pressure is given by

The angular speed of the tube is 31.321 rad/s
 
        
             
        
        
        
Answer:
no they can't talk to each other bcoz of the lack of atmosphere.
Explanation:
l hope it helps you
 
        
             
        
        
        
Answer:
d = 76.5 m
Explanation:
To find the distance at which the boats will be detected as two objects, we need to use the following equation:

<u>Where:</u>
θ: is the angle of resolution of a circular aperture 
λ: is the wavelength 
D: is the diameter of the antenna = 2.10 m 
d: is the separation of the two boats = ?
L: is the distance of the two boats from the ship = 7.00 km = 7000 m
To find λ we can use the following equation:
 
 
<u>Where:</u>
c: is the speed of light = 3.00x10⁸ m/s
f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz
 
            
Hence, the distance is:

Therefore, the boats could be at 76.5 m close together to be detected as two objects. 
  
I hope it helps you! 
 
        
             
        
        
        
Frequency = (speed) / (wavelength)
Speed = 3 x 10⁸ m/s
Wavelength = 3 cm = 0.03 m
Frequency = (3 x 10⁸  m/s) / (0.03 m)
Frequency = (3 x 10⁸ / 0.03) (m / m-s)
Frequency =  1 x 10¹⁰ Hz  (10 Gigahertz)
 
        
             
        
        
        
Answer:
     d = 142.5 m
Explanation:
This is a vector exercise. Let's calculate how much the boat travels in the 40s
      d₀ =  t
 t
     d₀ = 0.75 40
     d₀ = 30 m
Let's write the kinematic equations
Boat
      x = d₀  +   t
 t
      x = 0 +   t
 t
At the meeting point the coordinate is the same for both
     d₀  +   t =
 t =   t
 t
     t (  -
 -   ) = d₀
) = d₀  
     t = d₀  / (  -
-   )
)
The two go in the same direction therefore the speeds have the same sign
      t = 30 / (0.95-0.775)
      t = 150 s
The distance traveled by man is
      d =   t
 t
      d = 0.95 150
      d = 142.5 m