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Fofino [41]
3 years ago
6

For a series circuit what is the terminal voltage of a battery or power supply equal to in terms of the potential difference or

voltage drops across circuit components.
Physics
1 answer:
trapecia [35]3 years ago
7 0

Answer: V=IR

Explanation: for a series circuit connected to a battery supply, the total emf across the circuit is given as

E = I(R + r) and by expanding, we have that E =IR + It

Where r is the internal resistance of the battery

I is the total current flowing in the circuit

R total load resistance in the circuit.

E is the total emf of the circuit.

The total emf is the sum of 2 separate voltages.

"IR" which is the terminal voltage and "Ir" which is the loss voltage.

The teenila voltage is the voltage flowing in the circuit based on the equivalent resistance of the circuit while the loss voltage is the wasted voltage based on the internal resistance of the battery source.

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Answer:

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Explanation:

Given :

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In coordinate system ,

E=-\dfrac{dV}{\delta x }-\dfrac{dV}{\delta y }-\dfrac{dV}{\delta z }  { \delta is partial derivative }

Putting all values we get ,

E=-\dfrac{2xyz^2}{\delta x }-\dfrac{2xyz^2}{\delta y }-\dfrac{2xyz^2}{\delta z }\\\\E=-2yz^2-2xz^2-4xyz

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samantha a high school teacher wants to spend more time with her children and is looking for a job in her field. what would be a
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2 years ago
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Simple Circuit and Ohm's Law Check-for-Understanding
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