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Jobisdone [24]
3 years ago
10

In the hydrogen atom, what is the total energy of an electron that is in an orbit that has a radius of 8.784 × 10^(-10) m?

Physics
1 answer:
finlep [7]3 years ago
4 0

Answer:

The total energy of an electron in H atom is 1.31\times10^{-19}\ J.

Explanation:

Given that,

Radius R=8.784\times10^{-10}\ m

We need to calculate the orbit number

Using formula of radius

R=a_{0}n^2

n^2=\dfrac{R}{a_{0}}

Where, a₀ = boar radius

n = orbit number

Put the value into the formula

n^2=\dfrac{8.784\times10^{-10}}{0.529\times10^{-10}}

n=\sqrt{\dfrac{8.784\times10^{-10}}{0.529\times10^{-10}}}

n=4.07

We need to calculate the total energy of an electron in H atom

Using formula of energy

E=-\dfrac{13.6}{n^2}

Put the value into the formula

E=\dfrac{-13.6}{16.60}\ ev

E=0.8192\times1.6\times10^{-19}

E=1.31\times10^{-19}\ J

Hence, The total energy of an electron in H atom is 1.31\times10^{-19}\ J.

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