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quester [9]
3 years ago
10

Can you guys please help with this question?

Physics
1 answer:
Alexandra [31]3 years ago
3 0

they act as sunshades from the sun intensity, and filters

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Two satellites revolve around the Earth. Satellite A has mass m and has an orbit of radius r. Satellite B has mass 6m and an orb
melomori [17]

Answer:

aaaaa

Explanation:

M = Mass of the Earth

m = Mass of satellite

r = Radius of satellite

G = Gravitational constant

F=G\frac{Mm}{r^2}

F=G\frac{M6m}{r_b^2}

G\frac{Mm}{r^2}=G\frac{M6m}{r_b^2}\\\Rightarrow \frac{1}{r^2}=\frac{6}{r_b^2}\\\Rightarrow \frac{r_b^2}{r^2}=6\\\Rightarrow \frac{r_b}{r}=\sqrt{6}\\\Rightarrow r_b=2.44948r

r_b=2.44948r

8 0
4 years ago
What factor account for the change of viscosity in fluid
netineya [11]

Answer:

A fluid's viscosity strongly depends on its temperature. Along with the shear rate, temperature really is the dominating influence

Explanation:

The higher the temperature is, the lower a substance's viscosity is. Consequently, decreasing temperature causes an increase in viscosity.  

5 0
4 years ago
Which country sent the first artificial satellite into orbit?
Rasek [7]

the soviet union was the first country.



8 0
3 years ago
(1 point) A rectangular tank that is 3 feet long, 9 feet wide and 12 feet deep is filled with a heavy liquid that weighs 110 pou
Aloiza [94]

Answer:

Explanation:

Work in pumping water from the tank is given as

W = ∫ y dF. From a to b

Where dF is the differential weight of the thin layer of liquid in the tank, y is the height of the differential layer

a is the lower limit of the height

b is the upper limit of the height.

We know that, .

F = ρVg

Where F is the weight

ρ is the density of water

V is the volume of water in tank

g is the acceleration due to gravity

Then,

dF = ρg ( Ady)

We know that the density and the acceleration due to gravity is constant, also the base area of the tank is constant, only the height that changes.

Then,

ρg = 62.4 lbs/ft³

Area = L×B = 3 × 9 = 27ft²

dF = ρg ( Ady)

dF = 1684.8dy

The height reduces from 12ft to 0ft

Then,

W = ∫ y dF. From a to b

W = ∫ 1684.8y dy From 0 to 12

W = 1684.8y²/2 from 0 to 12

W = 842.4 [y²] from y = 0 to y = 12

W = 842.4 (12²-0²)

W = 121,305.6 lb-ft

3 0
3 years ago
A flat roof is very susceptible to wind damage during a thunderstorm and/or tornado. If a flat roof has an area of 500 m2 and wi
Evgesh-ka [11]

Answer: The magnitude of the force exerted on the roof is 490522.5 N.

Explanation:

The given data is as follows.

Below the roof, v_{1} = 0 m/s

At top of the roof, v_{2} = 39 m/s

We assume that P_{1} is the pressure at lower surface of the roof and P_{2} be the pressure at upper surface of the roof.

Now, according to Bernoulli's theorem,

P_{1} + 0.5 \times \rho \times v^{2}_{1} = P_{2} \times 0.5 \rho \times v^{2}_{2}

P_{1} - P_{2} = 0.5 \times \rho \times (v^{2}_{2} - v^{2}_{1})

             = 0.5 \times 1.29 \times [(39)^{2} - (0)^{2}]

             = 0.645 \times 1521

             = 981.045 Pa

Formula for net upward force of air exerted on the roof is as follows.

          F = (P_{1} - P_{2})A

             = 981.045 \times 500

             = 490522.5 N

Therefore, we can conclude that the magnitude of the force exerted on the roof is 490522.5 N.

5 0
3 years ago
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