If it starts from 0m/s...
s=?
u=0
a=-10
t=8
s=ut +1/2at^2
so s=(0×8)+ (0.5×-10×64)
s=0+(32×-10)
s=32×-10
s=-320metres
Answer:
c)by a factor of four
Explanation:
The total energy of a simple harmonic oscillator is given by

where
k is the spring constant of the oscillator
A is the amplitude of the motion
In this problem, the amplitude of the oscillator is doubled, so
A' = 2A
Therefore, the new total energy is

So, the total energy increases by a factor 4.
D is the answer because of the solar phonominals