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Yanka [14]
3 years ago
13

A lady bug is sitting on the bottom of a can while you twirl it overhead on a string that is 65.0

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

The linear speed of the ladybug is 4.1 m/s

Explanation:

First of all, we need to find the angular speed of the lady bug. This is given by:

\omega=\frac{2\pi}{T}

where

T is the period of revolution

The period of revolution is the time taken by the ladybug to complete one revolution: in this case, since it does 1 revolution every second, the period is 1 second:

T = 1 s

Therefore, the angular speed is

\omega=\frac{2\pi}{1 s}=6.28 rad/s

Now we can find the linear speed of the ladybug, which is given by

v=\omega r

where:

\omega=6.28 rad/s is the angular speed

r = 65.0 cm = 0.65 m is the distance of the ladybug from the axis of rotation

Substituting, we find

v=(6.28)(0.65)=4.1 m/s

Learn more about angular speed:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

#LearnwithBrainly

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3 years ago
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gayaneshka [121]

Answer:

1440 m

Explanation:

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3 years ago
State ohm’s law Q.34.7
defon

Ohm's law states that: V=RI

Explanation:

Ohm's law states that in a conductor, the potential difference across the conductor is directly proportional to the current flowing through it. Mathematically,

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V is the potential difference

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The constant of proportionality is called resistance (R), and it gives a measure of "how much the conductor opposes" to the flow of current. Therefore Ohm's law can be rewritten as

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where R is the resistance. By rewriting the equation as

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we see that the larger the resistance, the lower the current in the conductor.

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4 0
3 years ago
In a chemical reaction, the total mass of the reactants is 10.0 grams. The total mass of the products must be:
Nookie1986 [14]

Answer: exactly 10.0 grams.

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Identify the atom with the following ground-state electron configuration for its valence shell 4s23d104p6
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