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Basile [38]
2 years ago
11

Which of these is outside of the solar system? sun Saturn galaxy moon

Physics
2 answers:
pshichka [43]2 years ago
8 0

Our solar system consists of the sun and the 9 planets and their moons.

The galaxy is outside our solar system.

Shalnov [3]2 years ago
6 0

I would assume Galaxy, everything else is in our solar system.

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aleksklad [387]
1) A machine is an apparatus using or applying mechanical power and having several parts, each with a specific function.

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4) Measure a volume of an acid and place into a polystyrene cup which is placed into a beaker.
Measure the temperature of the acid with a thermometer.
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Have a wonderful day ✨❤️
3 0
3 years ago
When the ball on the table starts moving when the table is tilted
Elis [28]

Answer:

When the ball is placed on tilted tale it starts rolling because of the force of gravity pulls it downward along the plane of table and frictional force produces torque which generate rotational motion as a result body will start rolling.

Explanation:

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6 0
3 years ago
What gravitational force does the moon produce
saul85 [17]

Answer:

1.94\cdot 10^{20} N

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

The gravitational force is always attractive.

In this problem, we have:

m_1 = 5.98\cdot 10^{24}kg is the mass of the Earth

m_2 = 7.34\cdot 10^{22} kg is the mass of the Moon

r=3.88\cdot 10^8 m is the separation between the Earth and the Moon

Therefore, the gravitational force between them is

F=(6.67\cdot 10^{-11})\frac{(5.98\cdot 10^{24})(7.34\cdot 10^{22})}{(3.88\cdot 10^8)^2}=1.94\cdot 10^{20} N

6 0
3 years ago
Why is it important we uncover and study fossils?
Ilia_Sergeevich [38]

its important so we can learn things about the species  

4 0
3 years ago
Read 2 more answers
In his novel From the Earth to the Moon (1866), Jules Verne describes a spaceship that is blasted out of 12,000 yards/s. the Col
saw5 [17]

Answer:

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

Explanation:

Let suppose that spaceship is accelerated uniformly. A yard equals 0.914 meters. A feet equals 0.304 meters. If air viscosity and friction can be neglected, then acceleration (a), measured in meters per square second, is estimated by this kinematic formula:

a = \frac{v^{2}-v_{o}^{2}}{2\cdot \Delta s } (1)

Where:

\Delta s - Travelled distance, measured in meters.

v_{o}, v - Initial and final speeds of the spaceship, measured in meters.

If we know that v_{o} = 0\,\frac{m}{s}, v = 10968\,\frac{m}{s} and \Delta s = 212.8\,m, then the acceleration experimented by the spaceship is:

a = \frac{\left(10968\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (212.8\,m)}

a = 282652.782\,\frac{m}{s^{2}}

The acceleration experienced by the occupants of the spaceship during launch is 282652.782 meters per square second.

5 0
3 years ago
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