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3 years ago

Newton’s second law states that the acceleration of an object is dependent on 1 variable which is the net force

1 answer:

7 0

I think it’s false. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and then mass of the object.

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A car takes off from rest takes of from rest and covers a distance of 80m on a straight road in 10s.Calculate the magnitude of i

hodyreva [135]

Initial velocity (u) = 0 m/s [the car was at rest]
Distance (s) = 80 m
Time (t) = 10 s
Let the magnitude of acceleration be a.
By using the equation of motion, $s = ut + \frac{1}{2} a {t}^{2}$ we get, $80 = 0 \times 10 + \frac{1}{2} \times a \times {10}^{2} \\ = > 80 = \frac{1}{2} \times 100a \\ = > 80 = 50a \\ = > a = \frac{80}{50} \\ = > a = 1.6$

Answer:

The magnitude of its acceleration is 1.6 m/s^2.

Hope you could get an idea from here.

Doubt clarification - use comment section.

4 0

3 years ago

Which of the following is not a benefit of increased energy efficiency?

Rzqust [24]

From what I can see it's D, I did this by simply examining the other answers and seeing that they are beneficial, so, from that information, this one must not be.

7 0

3 years ago

The summer camps had a field trip from the campus to Fragrance Hill. They traveled at an average speed of 65 km/h in the first 2

ludmilkaskok [199]

Answer:

Explanation:

They traveled this distance in 2 parts, essentially. Part 1 had an average speed for a certain number of hours, part 2 had an average speed for a certain number of hours, and those 2 parts taken together took them a distance of 364 km. In equation form, that looks like this:

km/hr part 1 + km/hr part 2 = 364 km

Now we need to find each part on the left side of that equation. Part 1 first:

We traveled 65 km/hr for 2 hours, so that took us

$65\frac{km}{hr}*2hr$ and canceling out the hour label, we have that in part 1 we got

65(2) = 130 km. Good. Now onto the second part, where our unknown is.

We traveled 78 km/hr the second part for x hours, so that took us

$78\frac{km}{hr}*xhr$ and canceling out the hour label, we have that in part 2 we got

78x km. Now we can fill in the main equation (the one in bold print)

130 km + 78x km = 364 km and subtracting 130 km from both sides:

78x km = 234 km and dividing by 78 km:

x = 3 hours. Part 2 took 3 hours. Part 1 took 2 hours, so the whole trip took 5 hours.

7 0

3 years ago

Compressing the air by squeezing the bottle was accompanied by a(n) ________ in the temperature of air inside the bottle

Georgia [21]

Increase in temprature

3 0

3 years ago

What is the wavelength of a wave whose speed and period are 72.0 m/s and 5.00 s , respectively ?

uranmaximum [27]

Answer:

The distance between the two successive crests of the wave is 360m

Explanation:

Wavelength is defined as the property of wave in which the distance between identical points between two successive waves are calculated

Wavelength is referred to as the distance between two successive crests or troughs

Given that:

speed = 72.0 m/s

time = 5 seconds

Using the formula

C = fλ

Where C = speed, f = freequency and λ = wavelength

F = 1 / time

F = 1/5

F = 0.2Hz

From the fomula C = fλ

make λ the subject of the formula

λ = C / f

λ = 72/0.2

λ = 360m

3 0

2 years ago

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