Explanation:
It is given that total energy is -443 kJ/mol and formula to calculate the lattice energy is as follows.
Total energy = heat of sublimation + bond dissociation energies + ionization energy for Cs + EA of
+ lattice energy
-443 kJ/mol = 76 + 121 + 376 - 349 + Lattice energy
Lattice energy = (-443 - 76 -121 - 376 + 349) kJ
Lattice energy = -667 kJ
Therefore, we can conclude that -667 kJ is the magnitude of the lattice energy for CsCl.
Answer: <u><em>Shape and position</em></u>
Explanation:
<u><em>I just took the test and I got it correct</em></u>
<h3><u>Answer;</u></h3>
All the above
-street lights
-businesses
- Homes, etc
<h3><u>Explanation; </u></h3>
- Nuclear energy comes from splitting atoms in a reactor to heat water into steam, turn a turbine and generate electricity.
- Nuclear reactions are used to release nuclear energy that generate heat, which most frequently is then used in steam turbines to produce electricity in a nuclear power plant.
- Because nuclear power plants do not burn fuel, they do not produce greenhouse gas emissions.
- Nuclear energy may be used in a wide variety of fields as it generates high levels of electricity without causing damage to our environment and atmosphere.
Answer:
19.264×
atoms are present in 3.2 moles of carbon.
Explanation:
It is known that one mole of each element is composed of Avagadro's number of atoms. This is same for all the elements in the periodic table.
So, as 1 mole of any element = Avagadro's number of atoms = 6.02×
atoms
It is as simple as understanding a dozen of anything is equal to 12 pieces of that object.
As here the moles of carbon is given as 3.20 moles, the number of atoms in this mole can be determined as below.
1 mole of carbon = 6.02 ×
atoms
Then, 3.20 moles of carbon = 3.20 × 6.02 ×
atoms
Thus, 19.264×
atoms are present in 3.2 moles of carbon.
Answer:
10.28 mol
Explanation:
S + 2O = SO2
(atm x L) ÷ (0.0821 x K)
(3.45 x 45.6) ÷ (0.0821 x 373)
=5.13726
Then round it to significant figures
=5.14
5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)
=10.28 mol O