Refer to the diagram shown below.
g = 9.8 m/s², and air resistance is ignored.
For mass m₁:
The normal reaction is m₁g.
The resisting force is R₁ = μm₁g.
For mass m₂:
The normal reaction is m₂g.
The resisting force is R₂ = μm₂g.
Let a = the acceleration of the system.
Then
(m₁ + m₂)a = F - (R₁ + R₂)
(14+26 kg)*(a m/s²) = (65 N) - 0.098*(9.8 m/s²)*(14+26 kg)
40a = 65 - 38.416 = 26.584
a = 0.6646 m/s²
Answer: 0.665 m/s² (nearest thousandth)
If your engine is not at the right temprature, usually when it is too hot.
Answer:
The value of the acceleration of gravity of the Unknown Planet = 1.14 
Explanation:
length of the pendulum (L)= 1.15 m
Time period (T)= 6.29 seconds
We know that time period of a simple pendulum is given by
⇒ T = 2
×
put the values in the above formula we get
⇒ T = 2
× 
⇒ 6.29 = 2
× 
By solving the above equation we get
⇒ g = 1.14 
This is the value of the acceleration of gravity of the Unknown Planet.
Take a right triangle and apply pythagorean theorem where the displacement is the hypotenuse:
We get 36.25m
(9.8m/s) divided by 4m. the m's cancel out leaving you with s so 2.45s