Energy is neither created or destroyed true or false

Which is the BEST example of something that has kinetic energy?

drek231 [11]

Answer:

i am sure its the last one

4 0

3 years ago

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For the reaction N2(g) + 3H2(g) ↔ 2NH3(g), the equilibrium constant, K, = 9.83 x 10-2 at a certain temperature and pressure.

pshichka [43]

The reaction is not at equilibrium and it is in the forward direction.

a.

Given,

[N₂] = 0.910 mol / L

[H₂] = 0.3 mol / L

[NH₃] = 0.0081 mol / L

K = 9.83 x 10⁻²

The balanced chemical equation for the given reaction is,

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

The formula of equilibrium constant is given by,

K = [NH₃]² / [N₂] [H₂]²

9.83 x 10⁻² = [(0.0081)² ]/ [0.910 × (0.3)²]

⇒9.83 x 10⁻² = (0.00006561) / (0.0819)

⇒9.83 x 10⁻² = 0.0008010989

⇒0.00983 = 0.0008010989

LHS ≠ RHS

Hence, the reaction is not at equilibrium.

b.

The reaction is in forward direction.

Learn more about direction of the reaction from the link given below.

brainly.com/question/10278602

#SPJ1

4 0

2 years ago

What is percent of C in CO2 (C=12.01 amu, O=16.00 amu)

Luden [163]

Answer: 33%

Explanation: Because carbon atoms are only 1/3 of the compound since the other 2 atoms are oxygen. Like H20, Oxygen is one out of the three atoms in the compound.

7 0

4 years ago

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Two billiard balls having masses of 0.2 kg and 0.15kg approach each other. The first ball having a velocity of 2m/s hit the seco

Gekata [30.6K]

Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.

Explanation:

Given: $m_{1}$ = 0.2 kg, $m_{2}$ = 0.15 kg

$v_{1}$ = 2 m/s, $v_{2}$ = 0 m/s, $v'_{1}$ = ?, $v'_{2}$ = 1.5 m/s

Formula used is as follows.

$m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}$

where,

v = velocity before collision

v' = velocity after collision

Substitute the values into above formula as follows.

$m_{1}v_{1} + m_{2}v_{2} = m_{1}v'_{1} + m_{2}v'_{2}\\0.2 kg \times 2 m/s + 0.15 kg \times 0 m/s = 0.2 kg \times v'_{1} + 0.15 kg \times 1.5 m/s\\0.4 kg m/s + 0 = 0.2v'_{1} + 0.225 kg m/s\\0.2v'_{1} kg = 0.175 kg m/s\\v'_{1} = \frac{0.175 kg m/s}{0.2 kg}\\= 0.875 m/s$