For constant acceleration along a given direction, we can relate acceleration, velocity and position with the following equation that doesn't involve time:
In this equation x is the final position, which we take to be 0. Also the initial velocity Vo is zero. Thus the equation simplifies to
Putting in v=32m/s, a=-9.81m/s^2 gives
To get the speed of light in this class glass, used the following equation
v= c/n ; where c is the speed of light in a vacuum and n where the index of refraction
Based on my research the index of refraction of the class glass is 1.59
Given
c= 3.00 x 10^8 m/s
n= 1.59
Solution
we will use 3.00 for c to get the speed of light in class glass cause 10^8 m/s is fixed
v= 3.00 / 1.59
v= 1.886
So the speed of light in this class glass is 1.89 x 10^8 m/s
Explanation:
Given parameters:
Distance = 180m
Time = 12s
Unknown:
Speed in m/s and km/hr
Solution:
Speed is the distance divided by the time taken,
Speed =
So;
Speed = = 15m/s
1000m = 1km
3600s = 1hr
Therefore;
15 x m x x x = 54km/hr
second question: How many seconds after the first snowball
should you throw the second so that they
arrive on target at the same time?
Answer in units of s.
Answer:
Part 1: 28°
Part 2: 1.367
Explanation:
Part 1:
Given: 62°
Simple
θ = 90°- 62°
<u>θ = 28°</u>
Part 2:
Y-direction
Δy
Δt
Δt
<u>Δt= 1.367s</u>
Hope it helps :)